 | Frederick Emerson - Arithmetic - 1835 - 300 pages
...completed. Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down tht next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that,... | |
 | Benjamin Snowden - 1835 - 108 pages
...greater than the dividend, put a less figure than the last to the root, and alter the work. 8. — To the remainder bring down the next period for a new dividend, with which proceed as with the first dividend, until all the periods are brought down. Prove the work... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Lyman Cobb - Arithmetic - 1836 - 228 pages
...write the cube of this quotient figure, and call the amount the subtrahend. 1. Substract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. NOTE. — If the divisor can... | |
 | Mathematics - 1836 - 488 pages
...and add these three results together for a subtrahend. 4. Subtract the subtrahend from the dividend, to the remainder bring down the next period for a new dividend, and so proceed. Arithmetical and Geometrical Progression. Any rank of numbers more than two, increasing... | |
 | Benjamin Peirce - Algebra - 1837 - 300 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Benjamin Peirce - Algebra - 1837 - 302 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...figure of the root ; then place the square of it under the first period, and subtract it therefrom, and to the remainder bring down the next period, for a new dividend. Q. You have now found the first figure of the root ; what is the next process ? A. Double this first... | |
 | Horatio Nelson Robinson - Algebra - 1872 - 436 pages
...divisor; add the correction, and the result will be the complete diiàsor. V. Multiply tlie complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder briny down another period for a new dividend. YI. Add together the last complete divisor, the last... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
