 | Joseph Ray - Algebra - 1852 - 422 pages
...will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...unit's place of the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...right of the divisor ; multiply the divisor, thus increased, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting... | |
 | Horatio Nelson Robinson - 1868 - 430 pages
...correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the last complete divisor, the last correction,... | |
 | Robert Wallace - 1870 - 164 pages
...of the partial divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the whole root already found for a partial divisor, and... | |
 | Shelton Palmer Sanford - Arithmetic - 1872 - 404 pages
...of the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75... | |
 | Horatio Nelson Robinson - Algebra - 1872 - 436 pages
...and the result will be the complete diiàsor. V. Multiply tlie complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder briny down another period for a new dividend. YI. Add together the last complete divisor, the last... | |
 | Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...right of the divisor ; multiply the divisor, thus increase^, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...the root and at the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete divisor for... | |
 | Horatio Nelson Robinson - Algebra - 1875 - 430 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure,... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
