| Edward Brooks - Geometry, Modern - 1901 - 278 pages
...Similarly the second power of a number is called the square of the number. PROPOSITION V. — THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Given. — Let ABCD be any parallelogram, AB its base, and BE its altitude. To Prove. —... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. K a Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
| Arthur Schultze - 1901 - 260 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE... | |
| Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and... | |
| Metal-work - 1901 - 548 pages
...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two... | |
| Samuel Wesley Baird - Arithmetic - 1901 - 174 pages
...triangles ; but all can be formed by cutting quadrilaterals into two parts from corner to corner. As the area of a parallelogram is equal to the product of its base and altitude, so the area of a triangle, which is one half the parallelogram, is one half the... | |
| Arthur Schultze - 1901 - 392 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude... | |
| George Albert Wentworth - Geometry, Solid - 1902 - 248 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403. The area... | |
| Frank Joseph Schneck - Business mathematics - 1902 - 312 pages
...rectangle? How does the altitude of one ,, _' -F compare with that of the A Jit JJ , other? Principle. — The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude... | |
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