 | John Fair Stoddard - Arithmetic - 1868 - 356 pages
...last term of the 2d column for the TRUE DmSOE. Multiply this divisor by the last term of the roof, and subtract the product from the -dividend, and to the remainder annex the next period, for the SECOMD DIVIDEND. G. Proceed in like manner till all the periods have been used. NOTE. — 1. If... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...of the last figure; the sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down.... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...of tlic hist figure; the sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods arc brought down.... | |
 | Thomas Percy Hudson - Arithmetic - 1866 - 268 pages
...the root already obtained, and also to the partial divisor. Multiply the divisor thus formed by the last figure of the root, and subtract the product from the dividend, bringing down the next period to the right of the remainder for a dividend. Continue the operation... | |
 | Charles Davies - Algebra - 1867 - 322 pages
...root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the... | |
 | John Fair Stoddard - Arithmetic - 1888 - 480 pages
...right, to the last term of the 2d column for the TBUE DIVISOK. Multiply this divisor lij the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner till all the periods have been used. NOTE.— 1. If... | |
 | William Frothingham Bradbury - Algebra - 1868 - 264 pages
...right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, . subtract the product from the dividend, and to the...remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to the trial divisor, and bring down the next period... | |
 | William Frothingham Bradbury - Algebra - 1868 - 270 pages
...trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all (he periods have been employed.... | |
 | Joseph Ray - Arithmetic - 1857 - 358 pages
...to the trial divisor; the sum will be the COMPLETE divisor. 4. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend; to the remainder bring down the next period for a new dividend, and so proceed until all the periods... | |
 | Stoddard A. Felter - Arithmetic - 1868 - 360 pages
...the trial divisor, will form the complete dieisor. V. Multiply and subtract as in simple division, and, to the remainder, annex the next period for a new dividend. VI. Proceed in the same way, until all the periods are brouglit down. NOTES. — 1-. If the dividend... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
