...XII); that is, the two diagonals bisect each other in E. Therefore, the diagonals, etc. THEOREM XXIII. The area of a rectangle is equal to the product of its base by its altitude. Let ABCD be a rectangle. It D c is to be proved that its area is equal to the...

...rectangle equivalent to the square, but which cannot be made to coincide with it. FIG. 43. 417. THEOREM. The area of a rectangle is equal to the product of its base by its altitude (§ 160). 418. THEOREM. The area of a square, therefore, is equal to the square...

...two rectangles are to each other as the products of their bases by their altitudes. PROPOSITION IV. The area of a rectangle is equal to the product of its base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and altitude. PROPOSITION...

...represent them when they are measured by the linear unit (III., 8). PROPOSITION IV.— THEOREM. 9. Tlie area of a rectangle is equal to the product of its base and altitude. Let R be any rectangle, k its base, and h its altitude numerically expressed in terms of the linear...

...between 2809 sq. ft. Ï500 sy. ft., or У09 sg. it. 28'09 2500 50 3 502 = = 100 3 50x2 309 53 Ans. Since the area of a rectangle is equal to the product of its length and width, the width is equal to the area divided by the length. Therefore, the probable width...

...sides, and s their sum, A= V««-a)« If the triangle is equilateral and s = length of a side, 50. The Area of a Rectangle is equal to the product of its length and breadth, or A = bl where b = breadth and I = length. 51. The Area of a Parallelogram is...

...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured ? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable. Proposition...

...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. . CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable. Proposition...

...those of Newton and Leibnitz, is that it is true. Let us next take the following proposition : — The area of a rectangle is equal to the product of its base and altitude. This is first established in the case where the base and altitude are commensurable. It need only be...

...its altitude 39 inches. Reduce to the same unit, and compare. AnS. 4^-. Proposition 3. Theorem. 360. The area of a rectangle is equal to the product of its base and altitude. Hyp. Let R be the rectangle, b the base, and a the altitude expressed in numbers of the same linear...