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" In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. Let a: b = c: d — e :/= g: h. "
Elements of Plane and Solid Geometry - Page 134
by George Albert Wentworth - 1877 - 398 pages
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Surveying and Navigation: With a Preliminary Treatise on Trigonometry and ...

Aaron Schuyler - Navigation - 1873 - 536 pages
...give the continued proportions: AB : AE : : BC : BF :: CD : CG. AB : EB :: BC : FC :: CD : GD. Since the sum of the antecedents is to the sum of the consequents as one antecedent is to its consequent, we have, AD : AE+BF + CG : : AB : AE. NAVIGATION. Now let a right...
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Elements of Geometry and Trigonometry: From the Works of A.M. Legendre

Adrien Marie Legendre - Geometry - 1874 - 500 pages
...±2,0 : D ±^D -t qy T f which was to be proved. PEOPOSITION XI. THEOREM. In any continued proportion, the sum of the antecedents is to the sum of the consequents, as any antecedent to its corresponding consequent. From the definition of a continued proportion (D. 3), Adding and factoring,...
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The Southern Review, Volumes 10-11

Albert Taylor Bledsoe, Sophia M'Ilvaine Bledsoe Herrick - Reconstruction (U.S. history, 1865-1877) - 1872 - 496 pages
...oblique cone with a circular base. 5 66 The same proportion is true for every other element ; and since the sum of the antecedents is to the sum of the consequents as any one antecedent is to its consequent, we have I. Ad' : I. dc :: AD : DC; in which the symbol 2* is used...
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The Collegiate Algebra: Adapted to Colleges and Universities

James Bates Thomson, Elihu Thayer Quimby - Algebra - 1880 - 360 pages
...the sum of the third and fourth is to their difference. COR. 3. — In any number of equal ratios, the sum of the antecedents is to the sum of the consequents as any one antecedent is to its consequent. riH a + e + e + &c. a „ . . , , 5 -2 — - — = r = r = &c....
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Elements of Algebra

George Albert Wentworth - Algebra - 1881 - 406 pages
...Composition. a + c : c ::b -\- d: d. VII. Division. a — c:c::b — d:d. 350. In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. For if a - c - e - ff ' 5 2~/T r may be put for each of these ratios. Then ..rJr-.r.jf.r, .'. a = br,...
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Elements of Geometry

George Albert Wentworth - 1881 - 266 pages
...&ABC+ACD+ADE+AEF АABС ~ - &A'B'C' + A'C'D' + A' D' E' Л- A' Е' F' Д A' B' C' (in a series of equal ratios the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent). But АABC -А*-, §342 Л A' B' C' Ä1-Bß (similar A are to each other as the squares on their homologous...
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Elements of Geometry

George Albert Wentworth - Geometry, Modern - 1879 - 262 pages
...Now °L = 1. Subtract 1 from each member of the equation. Then f _ ! = c _ 1; that is, fL^6 = e^Ld, bd or, a — b : b : : c — d : d. QED PROPOSITION...consequents as any antecedent is to its consequent. Let a :6 = c : d — e : f = g : h. We are to prove -a + c+e + g: b + d+f+h: : a: b. Denote each ratio*by...
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Elements of Plane Geometry

Franklin Ibach - Geometry - 1882 - 208 pages
...on \ Then or a ± £- a : b ± £- b :: a : b. QED THEOREM XIII. 168. In any continued proportion, the sum of the antecedents is to the sum of the consequents...to its consequent. Let a : b :: c : d :: e : f :: g : h. To prove that a -\- c -\- e -\- y : b -{- d -\- f -\- h :: a : b. Denote the common ratio by r....
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Elements of Plane Geometry

Franklin Ibach - Geometry - 1882 - 208 pages
...q / \ q ' or a ± — a : 6 ± — 6 : : a : b. QED THEOREM XIII. 168. In any continued proportion, the sum of the antecedents is to the sum of the consequents...as any antecedent is to its consequent. Let a : b :: с : d :: e : f :: g : h. To prove that a -\- с -\- e -\. g : b -\- d -{. f .\. h :' a : b. Denote...
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Elements of Geometry

George Albert Wentworth - Geometry, Modern - 1882 - 268 pages
...PROPOSITION VIIL 266. In a series of equal ratios, the sum of the antecedents is to the sum of tlie consequents as any antecedent is to its consequent. Let a : b = c : d = e :f — g : h. We are to prove a + с + e + g : b + d + f+ h : : a :b. Denote each ratio by r. Then r. •.'«'.!....
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