 | Arithmetic - 1817 - 214 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. ln«olve the root to the next inferior power to... | |
 | Thomas Keith - Arithmetic - 1822 - 354 pages
...left-hand period, and put the root thereof in the quotient ; subtract this square from the left-hand period, and to the remainder bring down the next period for a dividend. 3. Double the quotient for a divisor, then consider what figure must be annexed to the right... | |
 | Jacob Willetts - Arithmetic - 1822 - 200 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividual. 3. Involve the root to the next inferior power to that... | |
 | Beriah Stevens - Arithmetic - 1822 - 436 pages
...lesser root of the left hand period, put the figure so found in the quotient, subtract its fifth power, and to the remainder bring down the next period for a resolvend. 2 Put afy for the root, and then the sursolid or fifth pother will be aaaart-r-5aaaay+10aanyy-f-aayy+5ayyy+yj'yyy.... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...hand period, which place to the right of the given number, and subtract the cube thereof from said period; and to the remainder bring down the next period for a dividual. j ?,.'•.. Thirdly, Take the triple square of the ascertained root for a defective divisor.... | |
 | Martin Ruter - Arithmetic - 1828 - 180 pages
...given number, is such a number as being multiplied by itself, and then into that product, preduces the given number. RULE. 1. Point off the sum into...the defective divisor is contained in the resolvend, omilt'np the units and tens, or two right hand figures. Place the result in the quotient, and its square... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...number in the left hand period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seekhow many times the divisor is contained... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...number in the left band period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...left-hand period, and place its root in the quotient. 3. Subtract the cube thus found from the said period, and to the remainder bring down the next period for a resolvend. 4 Multiply the square of the quotient by 300, calling it the divisor. 5. Seek how often the divisor... | |
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... from the left hand period, and to the remainder bring down the next period for a dividend. 
