 | Commissioners of National Education in Ireland - Measurement - 1841 - 286 pages
...Ans. 1164 feet 4 inches 6 parts. PROBLEM III. To find the area of a rhombus. RULE. Multiply the j^ length by the perpendicular breadth, and the product will be the area.* 1. What is the area of a rhombus, whose side is 16 feet, and perpendicular breadth 10 feet? Ans. 16... | |
 | Joseph Gwilt - Architects - 1842 - 1114 pages
...length of the measuring unit is contained in AD or BC, will give 1 2 for the product. 1214. PROBLEM I. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Multiply the length by the perpendicular breadth or height, and the product will be the area. .F,g.... | |
 | Osman Call - Arithmetic - 1842 - 200 pages
...COMPREHENDS THE ADMEASUREMENT OF SURFACES, AND THE SOLID CONTENTS OF BODIES. TO FIND THE AREA OF ANY PARALLELOGRAM, WHETHER IT BE A SQUARE, A RECTANGLE, A RHOMBUS, OR A RHOMBOID. RULE. — Multiply the length by the perpendicular breadth or height, and the product will be the area. What... | |
 | Isaac A. Clark - Arithmetic - 1846 - 218 pages
...measure of solids; this measure considers the length, breadth and thickness; ie, the solid conents. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or rhomboids. DC Square. § Place the length of the base and the perpendicular height on the right, and... | |
 | John Gummere - Surveying - 1846 - 448 pages
...the area of each may be found ; and the sum of these areas will be the area of the tract. PROBLEM I. To find the area of a Parallelogram, whether it be a Square, a Rectangle, a RJiombus, or a Rhomboides. RULE. Multiply the length by the height or perpendicular breadth, and the... | |
 | William Templeton (engineer.) - 1846 - 236 pages
...length and hreadth, without having any regard to the thickness. PROBLEM I. To find the urea of any parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. RULE. — Multiply the length by the breadth or height, and the product will be the area. Square. Rectangle.... | |
 | 458 pages
...— 134 THE DECORATOR'S ASSISTANT. JffiUnsuratton of Super$res. PROBLEM I. (Continued from page 128.) To find the area* of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboides. 1. Required the area of the square AB c D, whose side is 5 ft. ? 20. Best Body Copal Varnish... | |
 | Charles William Hackley - Geometry - 1847 - 248 pages
...the rectangle is said to contain, which in the present case is 12. PROBLEM I. To find the area of any parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Multiply the length by the perpendicular breadth or height, and the product will be the area.* * The... | |
 | Basil Jackson - Military reconnaissance - 1847 - 410 pages
...is called 4 inches, and perpendicular 3 inches ; and 3x4=12 square inches. To find the area of any parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Multiply the length, stated in any linear measurement, as inches, links, feet, yards, &c., by the perpendicular... | |
 | John Bonnycastle - Geometry - 1848 - 320 pages
...observing this rule will generally find his results to agree with those given in the book. PROBLEM I. To find the area of a parallelogram ; whether it be a square, a rectangle, a rhombus, or a rhomboidfs. RULE.* Multiply the length by the perpendicular height, and the product will be the area.... | |
| |
PROBLEM I. To find the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboides. 
