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" In one of the given equations obtain the value of one of the unknown quantities in terms of the other unknown quantity; Substitute this value in the other equation and solve. "
An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to ... - Page 126
by John D. Williams - 1840 - 605 pages
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The principles of arithmetic. [Followed by] The principles of algebra

Wales Christopher Hotson - 1842 - 306 pages
...unknown quantity may be obtained by any of the following methods. First Method. In either equation, find the value of one of the unknown quantities in terms of the other and known quantities, and for it substitute this value in the other equation, which will then contain only one unknown quantity;...
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Elimination Between Two Unknown Equations with Two Unknown Quantities, by ...

Francis Henney Smith - Curves, Algebraic - 1842 - 70 pages
...and we should, in general, obtain a determinate number of solutions. It would be only necessary to find the value of one of the unknown quantities in terms of the others, in one of the equations, and substitute this value in each of the other equations ; there would...
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Elements of Algebra: Being an Abridgment of Day's Algebra, Adapted to the ...

James Bates Thomson - Algebra - 1844 - 266 pages
...process is called extermination by substitution. Hence, 279. CASE II. To exterminate an unknown quantity by substitution. Find the value of one of the unknown quantities, in one of the equations ; and then in the other equation, SUBSTITUTE this value for the unknown quantity...
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The first principles of algebra, for the use of the boys of the Royal ...

Admiralty - 1845 - 152 pages
...of '2 to 3. The parts are found to be 12 and 18. 67. Rule 2. — From either of the given equations, find the value of one of the unknown quantities in terms of the other quantities ; substitute this value for the same quantity in the other equation ; which equation will...
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A system of practical mathematics; being no.xvi. of a new series of school-books

Scottish school-book assoc - 1845 - 444 pages
...only the other unknown, from which its value can be found by the previous rules. 74. RULE III. Find a value of one of the unknown quantities in terms of the other from one of the equations, and substitute this value instead of it in the other, from which there will...
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The elements of algebra, with additions by W. Galbraith and W. Rutherford

John Bonnycastle - 1848 - 334 pages
...methods may be employed for the solution of such equations. First method. — Find the value of either of the unknown quantities in terms of the other and known quantities from each equation ; then put these two values equal to each other, and there will be formed an equation...
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Elements of Algebra: Being an Abridgment of Day's Algebra, Adapted to the ...

Jeremiah Day, James Bates Thomson - Algebra - 1848 - 264 pages
...process is called extermination by substitution. Hence, 279. CASE IL To exterminate an unknown quantity by substitution. Find the value of one of the unknown quantities, in one of the equations ; and then in the other equation, SUBSTITUTE this value for the unknown quantity...
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An Introduction to Algebra, and to the Solution of Numerical Equations

John Radford Young - 1851 - 266 pages
...will accomplish the object sought, 56. To solve two simultaneous simple equations: — First Method. Find the value of one of the unknown quantities in terms of the other unknown and the known quantities, from the first equation : that is, proceed exactly as if there were...
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Elements of Algebra: On the Basis of M. Bourdon, Embracing Sturm's and ...

Charles Davies - Algebra - 1857 - 408 pages
...quantities, when one of the equations is of the second degree, and the other of the first. For, we can find the value of one of the unknown quantities in terms of the other and known quantities, from the latter equation, and by substituting this in the former, we shall have a single equation of...
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A graduated series of exercises in elementary algebra

George Farncomb Wright - 1857 - 98 pages
...simultaneous Equations of the following Exercise may all be solved by deriving, from one of the Equations, the value of one of the unknown quantities in terms of the other, and substituting this value in the second of the proposed Equations. The student will occasionally, however,...
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