Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. A Treatise on Algebra - Page 141by Elias Loomis - 1868 - 384 pagesFull view - About this book
| Nicolas Pike - Arithmetic - 1832 - 544 pages
...the cube of the last quotient figure, and call their sum the subtrahend. 5. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for anew dividend, with whieh proceed as before, and so on until the whole be finished. EXAMPLE. Required... | |
| Lyman Cobb - Arithmetic - 1832 - 228 pages
...wiite the cube of this quotient figure, and call the amount the subtrahend. 7. Substract the subtrahend from the dividend, and to the remainder bring down the next period for anew dividrnd, with wiiieh proceed HS before; anci so on, till the whole is finished. NOTE. — If... | |
| John Radford Young - Algebra - 1832 - 408 pages
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37), the cube of a + b is a3 + 3a2¿... | |
| Samuel Read Hall - Arithmetic - 1832 - 294 pages
...the last quotient, and cube the last quotient, and add these products together and take the amount from the dividend. and to the remainder bring down the next period. Proceed as before, till the whole is finished. 1. What is the cube root of 15625? 15625(25 root The... | |
| Charles Davies - Arithmetic - 1833 - 284 pages
...right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
| Daniel Adams - Arithmetic - 1833 - 268 pages
...the cube of this quotient figure, and call their amount the subtrahend. VII. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. Note 1. If it happens that the... | |
| William Templeton (engineer.) - 1833 - 224 pages
...in the root ; add these three last found numbers together, and subtract this sum from the dividend ; to the remainder bring down the next period for a new dividend, and proceed as before. EXAMPLE. — Required the cube root of 44419494". 444194947(763 343 7 x 7 x... | |
| Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...and add these three results together for a subtrahend. 5. Subtract the subtrahend from the dividend. To the remainder bring down the next period, for a new dividend, and proceed as before. If it happens in any case, that the divisor is not contained in the dividend,... | |
| Frederick Emerson - Arithmetic - 1834 - 300 pages
...completed. Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the...remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that, when the divisor is not contained in... | |
| Charles Davies - Algebra - 1835 - 378 pages
...right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
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