 | Bourdon (M., Louis Pierre Marie) - Algebra - 1850 - 386 pages
...(60) 2 + 2 x 60 X 4 + (4) 2 = 4096. Hence, the square of a number composed of tens and units contains, the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each a cipher, we shall have,... | |
 | Charles Davies - Algebra - 1850 - 292 pages
...-j-2ao-{-6 2 =:4096. Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1, 2, 3, 4, &c, tens, or units of the second order, by annexing to each... | |
 | James Robinson - Arithmetic - 1850 - 342 pages
...tens; hence, we infer that the second power of every number composed of tens and units must contain the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. We will now reverse the process of finding the... | |
 | Charles Davies - Algebra - 1851 - 300 pages
...or a»+2aJ+6 2 =4096. Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1, 2, 3, 4, &c, tens, or units of the second order, by annexing to each... | |
 | Thomas Sherwin - 1851 - 266 pages
...+ 9 = 529. Hence, When a number contains units and tens, its second power contains the second power of the tens, plus twice the product of the tens by the units, plus the second power of the units. Let us now, by a reverse operation, deduce the root from the power. Operation.... | |
 | James Robinson (Jr.) - Arithmetic - 1851 - 336 pages
...tens; hence, we infer that the second power of every number composed of tens and units must contain the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. We will now reverse the process of finding the... | |
 | Charles Davies - Arithmetic - 1852 - 422 pages
...of the square AE, the two rectangles FE and EC, and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two... | |
 | Charles Davies - Arithmetic - 1852 - 438 pages
...of the square AE, the two rectangles FE and EC, and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two... | |
 | Gerardus Beekman Docharty - Algebra - 1852 - 298 pages
...have or a'+2a&+6'=400+280+49 =729. Hence the square of a number composed of tens and units consists of the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. If we reverse this process, we shall find the square root of the number. We perceive that the square... | |
 | Elias Loomis - Algebra - 1852 - 366 pages
...number of tens, whose square is 400 ; and if we subtract this from 529, the remainder 129 contains twice the product of the tens by the units, plus the square of the units. If, then, we divide this remainder by twice the tens, we shall obtain the units, or possibly a number... | |
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square of a number consisting of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. Using t and u respectively to denote the tens and units of a number, we have the FORMULA... 
