| Military Academy, West Point - 1934 - 964 pages
...the expansion of ( rr'-rJ.'1 )' by the binomial theroem. and simplify * result. \rr ' 2. Prove that **the angle formed by a tangent to a circle and a chord** is measured by one-half Its int«rap£K aro. 3. The sum of the ages of a father and his son is 100... | |
| United States Military Academy - 1942
...expansion of ( -я— =vs )' by the Binomial Thereom. and simplify the result. Ч» 2 / 2. Prove that **the angle formed by a tangent to a circle and a chord** is measured by one-half its intercepted arc. 3. The sum of the ages of a father and his son is 100... | |
| Research & Education Association Editors, Ernest Woodward - Mathematics - 2012 - 1080 pages
...determine the measure of each arc drawn, and then apply the theorem stating that the measure of an **angle formed by a tangent to a circle and a chord drawn from the point of contact is equal to** one-half the measure of its intercepted arc. *DBC is formed in just such a way, and its measure is... | |
| Ovid Wallace Eshbach, Byron D. Tapley - Technology & Engineering - 1990 - 2176 pages
...intercepted by it. Thus, in Fig. 2.14. ZBAC - J arc BC. An angle inscribed in a semicircle is a right angle. **The angle formed by a tangent to a circle and a chord** having one extremity at the point of contact equals half the arc intercepted by the chord. In Fig.... | |
| Linda Bostock, F. S. Chandler, A. Shepherd - 1992 - 392 pages
...A) => q' =9 But 'r is equal to any angle subtended by the chord TR, ie the angle between a tangent **and a chord drawn from the point of contact is equal to** any angle in the alternate segment. EXERCISE 11f In questions 1 to 4, copy the diagram and shade the... | |
| L. Bostock - Mathematics - 1998 - 420 pages
...external point to a circle are the same length. The angle between a tangent and a chord drawn through **the point of contact is equal to the angle in the alternate segment.** This result is called the alternate segment theorem. EXERCISE 3.5 1 Find the marked angles. a 2 Find... | |
| Paul Hogan, Barbara Job, Diane Morley - General Certificate of Secondary Education - 1999 - 240 pages
...perpendicular to radius) So a = 90°- (90° -p) a=p b The angle between a tangent and a chord drawn to **the point of contact is equal to the angle in the alternate segment.** (Alternate Segment Theorem.) Exam questions 1 135° 2 (1) 9.6cm 3 8.25cm (2) 3 cm 3cm 3 cm / 6 Side,... | |
| David Baker - General Certificate of Secondary Education - 2002 - 580 pages
...:¿¿s not cross the segment with ) _____________ The angle between a tangent and a chord drawn to **the point of contact is equal to the angle in the alternate segment.** This is the last result that you need to learn from this section! Now you need to be able to use all... | |
| Lyn Baker - Higher School Certificate Examination (N.S.W.) - 2002 - 154 pages
...tangents to a circle from an external point are equal • the angle between a tangent and a chord through **the point of contact is equal to the angle in the alternate segment** • the square of the length of a tangent from an external point is equal to the product of the intercepts... | |
| David Baker - General Certificate of Secondary Education - 2001 - 748 pages
...circumference. The angle in a semi-circle is 90°. The angle between a tangent and a chord drawn to **the point of contact is equal to the angle in the alternate segment** Proofs of the circle theorems. Notes for the non-specialist: Pupils are told the simple results early... | |
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