 | Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...result in the root and at the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...their sum will be the divisor completed. VI. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. VII. Thus proceed till the whole root is obtained. To find each successive... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Milton Browning Goff - Arithmetic - 1876 - 462 pages
...root ; 2d. The square of the last figure of the root. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Form, in the same manner, successive divisors, and find corresponding figures... | |
 | Edward Brooks - Arithmetic - 1876 - 588 pages
...the root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as tens, for a trial... | |
 | William Guy Peck - Arithmetic - 1877 - 430 pages
...product to the trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial -figure of the root, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till all the periods... | |
 | Joseph Ray - Arithmetic - 1877 - 402 pages
...and also on the right of the trial divisor. P«c. •» 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor,... | |
 | William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The... | |
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Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
