| John Keill - Geometry - 1782 - 399 pages
...Therefore the Angle KFG is equal to the Angle CF L. And fo FKC, FLC, are two Triangles, having two An' gles **of the one equal to two Angles of the other, each to each, and** one Side of the one equal to one 6iJe of the other, viz. the common Side FC ; wherefore they f z«.... | |
| John Playfair - Euclid's Elements - 1795 - 444 pages
...EDF. Wherefore, if two triangles, &c. Q., ED a 4. i. b 34. i. PROP. XXVI. THEO R. IF two triangles **have two angles of the one equal to two angles of the other, each to each ; and** one fide equal to one fide, viz. either the fides adjacent to the equal angles, or the fides oppofite... | |
| Benjamin Donne - 1796 - 118 pages
...nwji be equal to the remaining angle of the other. THEOREM 15. If two triangles have two angles of **one equal to two angles of the other, each to each, and** one s1de of one equal to one D side side of the other, the triangles are equal in every refpcEl. —... | |
| Alexander Ingram - Trigonometry - 1799 - 351 pages
...Therefore, &c. Q^ ED COR. Likewife, if two folid angles be each contained by three plane angles, and **have two angles of the one equal to two angles of the other,** and thefe angles be in planes which have the fame inclination to one another ; the third angle of the... | |
| Tiberius Cavallo - Aeronautics - 1803 - 638 pages
...die angle FGD is equal to the angle CGD; whence it follows, that the triangles DGC and DGF, Tiaving **two angles of the one equal to two angles of the other,** and a correfpondent fide, viz. DG, common, are equal in every refpect J ; * It is ufelefs to take notice... | |
| John Playfair - Euclid's Elements - 1804 - 470 pages
...by BD ; and becaufe the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD **have two angles of the one equal to two angles of the other** ; and the fide BD, Which is oppofite to one of the equal angles in each, is common to both; therefore... | |
| Robert Simson - Trigonometry - 1804
...bifefted by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FED **have two angles of the one equal to two angles of the other,** and the fide BD,' which is oppofite to cme of the TJ -Tf |N| eq*MfiB(fcgles in each, is common*"^ *... | |
| Robert Simson - Trigonometry - 1806 - 518 pages
...is equal to the right angle FCL: therefore, in the two triangles FKC, FLC, there are two angles of **one equal to two angles of the other, each to each, and the side** FC, which is adjacent to the equal angles in each, is common to both ; therefore the other sides shall... | |
| John Playfair - Euclid's Elements - 1806 - 311 pages
...FCK is equal to the right angle FCL. Therefore in the two triangles FKC, FLC, there are two angles of **one equal to two angles of the other, each to each, and the side** FC, which is adjacent to the equal angles in each, is common to both; therefore the straight line KC... | |
| Charles Butler - Mathematics - 1814 - 528 pages
...(viz. at D,) and the angles ABD, CAD equal ', and also the side AD common ; these triangles therefore **have two angles of the one equal to two angles of the other, each to each,** but the common side AD not lying either between given, or opposite equal angles, the triangles are... | |
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