 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Note. — When the base and altitude are given, the area is equal to the base multiplied by half the... | |
 | Thomas Hunter - Geometry, Plane - 1878 - 142 pages
...sides only are given. EULE. — From half the sum of the three sides subtract each side sepa~ rately : multiply the half sum and the three remainders continually...square root of the product will be the area required.* • Demonstration.—Let AC=c, CB=<7, and AB=6; and c»—d'=AD a —DB» (e+d) (f—d)=(AD+DB) (AD—DB);... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area required. NOTE. — When the base and altitude are given, the area is equal to the base multiplied by half the... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 292 pages
...of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area required. NOTE. — When the base and altitude are given, the area is equal to the base multiplied by half the... | |
 | Frederick Thomas Hodgson - Carpentry - 1883 - 168 pages
...and from half the sum subtract each side separately; then multiply the half sum and the three sides together, and the square root of the product will be the area required. Let the sides of a triangle be 30, 40, and 50 ft. respectively. 30 + 40+50 120 2 60, half the sum of... | |
 | Colin Arrott R. Browning - 1884 - 274 pages
...the perpendicular. Rule : — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root of this product will be the area of triangle. (16) In a right-angled triangle the side opposite to the... | |
 | Euclides - 1884 - 434 pages
...of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area.* 1. If from B there be drawn BE j_ AC or AC produced, then BC . CD = AC . CE. 2. ABCD is a ||m having... | |
 | Joseph Gregory Horner - Engineering - 1906 - 572 pages
...of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area. This is more conveniently stated and easier remembered if put in the form of a formula. If the three... | |
 | 1906 - 576 pages
...of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area. This is more conveniently stated and easier remembered if put in the form of a formula. If the three... | |
 | William Miller Barr - Engineering - 1918 - 650 pages
...thus: Rule: From half the sum of the four sides subtract each side severally; then multiply the four remainders continually together, and the square root of the product will be the area. To Find the Area of a Trapezoid, or a Quadrangle, Two of Whose Opposite Sides Are Parallel. — Rule:... | |
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Multiply the half sum and the three remainders continually together, and the square root of the product will be the area... 
