 The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R.  A Geometry for Beginners - Page 128by George Anthony Hill - 1880 - 314 pagesFull view - About this book
 | Edward Brooks - Geometry - 1868 - 284 pages
...other. It is one of the most interesting and practical books of Geometry. AREA OF POLYGONS. THEOREM I. The area of a rectangle is equal to the product of its base and altitude. Let ABCD be a rectangle; then will its area be equal to the product of its base... | |
 | John Reynell Morell - Geometry - 1871 - 156 pages
...an inch, a foot, &c. Plane figures that have equal superficial extension are called equivalent. 109. The area of a rectangle is equal to the product of its base by its height. This proposition is easily deduced from the simple inspection of Figure 89. The area of every... | |
 | William Chauvenet - Geometry - 1871 - 380 pages
...represent them when they are measured by the linear unit (III. 8). PROPOSITION III.— THEOREM. 7. The area of a rectangle is equal to the product of its base and altitude. Let R be any rectangle, If its base and h its altitude numerically expressed in... | |
 | William Chauvenet - Geometry - 1872 - 382 pages
...which represent them when they are measured by the linear unit (III. 8). PROPOSITION III.—THEOBEM. 7 The area of a rectangle is equal to the product of its base and altitude. Let R be any rectangle, k its base and h its altitude numerically expressed in terms... | |
 | Edward Olney - Geometry - 1872 - 562 pages
...regarding the unit of measure as infinitesimal, and consequently is to be neglected.* Hence, in any case, the area of a rectangle is equal to the product of its base into its altitude, ij. KD 321. COB. 1. — The area of a square is equal to the second power of... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...linear unit, the rectangle AEGF will be Iho superficial unit, and we shall have, ABCD = AB x AD : hence, the area of a rectangle is equal to the product of its base and altitude; that is, the number of superficial un1ts in the rectangle, is equal to the product... | |
 | William Frothingham Bradbury - Geometry - 1872 - 124 pages
...polygon ABCDEF will coincide with the polygon GHI KLM, and therefore be equal to it. THEOREM II. T, The area of a rectangle is equal to the product of its bast and altitude. B 0 PQKC IJKD Let ABCD be a rectangle ; its area = ADXA B. Suppose AB and AD to... | |
 | Edward Olney - Geometry - 1872 - 472 pages
...polygon of any number of sides to an equivalent triangle. A AREA. PROPOSITION TI. 320. Theorem. — The area of a rectangle is equal to the product of its base and altitude. DEM.— Let ABCD be a rectangle, then is its area equal to the base AB multiplied... | |
 | William Frothingham Bradbury - Geometry - 1872 - 262 pages
...polygon ABC DEF will coincide with the polygon GHIKLM, and therefore be equal to it. THEOREM II. 1, The area of a rectangle is equal to the product of its base and altitude. B 0 JKD Let A BCD be a rectangle ; its area = A II XA B. Suppose AB and AD to bo... | |
 | Daniel W. Fish - Arithmetic - 1874 - 302 pages
...of each rectangle. The units' figure of the root is equal to the width of one of these rectangles. The area of a rectangle is equal to the product of its length and width (4G2) ; hence, if the area be divided by the length, the quotient will be the width.... | |
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