 | Silas Ellsworth Coleman - Arithmetic - 1897 - 180 pages
...From this example we may deduce the following rule for the multiplication of algebraic quantities : Multiply each term of the multiplicand by each term of the multiplier. * This article may be omitted at the discretion of the teacher. When the two terms of a product have... | |
 | 1897 - 358 pages
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
 | International Correspondence Schools - Surveying - 1898 - 146 pages
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
 | George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1898 - 712 pages
...preceding article is derived the following principle for multiplying a multinomial by a multinomial: Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. Ex. l. Multiply -3a + 2& by 2a-36. We have -36x26 (1)... | |
 | Seymour Eaton - 1899 - 362 pages
...Lesson No. 9. Algebraic Multiplication (Continued) To multiply one compound expression by another, multiply each term of the multiplicand by each term of the multiplier, and add results for the complete answer. To find the product of a + b and c + d. (o+6) x(c + d) = (a... | |
 | International Correspondence Schools - Civil engineering - 1899 - 722 pages
...Ans. (14) ln the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
 | William J. Milne - Algebra - 1899 - 172 pages
...+ b a times a + 6 = a'2 + a6 6 times a + b = ab + Ift (a + 6) times (a + 6) = a2 + 2 ab + 6" RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 3. 2 ab - 3 ca? x — y ;26'2- lOa6c-Sc2 & Multiply : 4. x + ybyx... | |
 | George Edward Atwood - 1900 - 276 pages
...a polynomial. RULE. — Arrange the multiplicand and multiplier with reference to the same letter. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 2- 3a263+ 2o64 +26* b3 — 6a464+ - 8a464+ a —b +2 c +x -3... | |
 | James Morford Taylor - Algebra - 1900 - 504 pages
...22. 2\3ab-4:a(c-2b')l. 23. 7ac-2{2c(a-3&)-3(5c-2Z»)a|. 79. To multiply one polynomial by another, Multiply each term of the multiplicand by each term of the multiplier, and add the resulting products. Proof. Let x + y + z be the multiplicand, and a + b the multiplier... | |
 | George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1900 - 202 pages
...3x7-3x5. This example illustrates the following method of multiplying a multinomial by a multinomial : Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. In general, (a + 6)(c + d- e) = a(c + d- e) + b(c + d-... | |
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Place the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier separately... 
