 | Euclides - 1845 - 546 pages
...F, that CD is of F: wherefore KH is equal to CD: (v. ax. 1.) take away the common magnitude CH, then the remainder KC is equal to the remainder HD : but KC is equal to F ; (constr.) therefore HD is equal to F. Next let GB be a multiple of E. Then HD shall be the same multiple... | |
 | Euclid - Geometry - 1845 - 218 pages
...multiple of F, that CD is of F ; wherefore KH is equal to CD* : Take away the common magnitude CH, then the remainder KC is equal to the remainder HD : but KC is equal f to F ; HD therefore is equal to F. But let GB be a multiple of E ; then HD is the same multiple of... | |
 | Euclides - 1846 - 292 pages
...F, and therefore KH is equal to CD (3. Ac. 1) : Take away the common magnitude CH from both ; then the remainder KC is equal to the remainder HD : But KC is equal to F ; therefore HD is equal to F. Next, let GB be a multiple of E : HD shall be the same multiple of F. Make CK the same... | |
 | Euclides - 1855 - 270 pages
...that CD is of F; and KH is equal to CD (V. Ax. 1). From these equals, take the common magnitude C H. The remainder KC is equal to the remainder HD. But KC is equal to F (Const.). Therefore HD is equal to F. Next let GB be a multiple of E. HD is the same multiple of F.... | |
 | Euclides - 1863 - 122 pages
...of F; and KH is equal to CD (V. Ax. 1> ECHD FFrom these equals take the common magnitude CII. Th,; remainder KC is equal to the remainder HD. But KC is equal to F (Const.) Therefore HD is equal to F. Next let GB be a multiple of E. HD is the same multiple of F.... | |
 | Robert Potts - 1865 - 528 pages
...that CD is of .F: wherefore KH>s equal to CD: (v. ax. 1.) take away the common magnitude CiI, then the remainder KC is equal to the remainder HD : but KC is equal to F: (constr.) therefore HD is equal to F. Next let GB be a multiple of E. Then Hfi shall be the same multiple... | |
 | Euclides - 1865 - 402 pages
...that CD is of F ; wherefore KH is equal to CD ; (v. ax. 1.) take away the common magnitude CH, then the remainder KC is equal to the remainder HD ; but KC is equal to F ; (constr.) therefore HD is equal to F. Secondly, let GB be a multiple of E. Then HD shall be the same... | |
 | Euclid - 1868 - 138 pages
...that CD is of F; and therefore KH is equal to CD. From these equals, take the common magnitude CH. The remainder KC is equal to the remainder HD. But KC is equal to F; therefore HD is equal to F. In like manner we can show that if GB be a multiple of E, HD will be the same multiple... | |
 | Robert Potts - 1868 - 434 pages
...F, that CD is of F: wherefore KHis equal to CD: (v. ax. 1.) take away the common magnitude CH, then the remainder KC is equal to the remainder HD : but KC is equal to F: (constr.) therefore HD is equal to F. Next let GB be a multiple of E. Then HD shall be the same multiple... | |
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GB is equal to E, and CK to F ; therefore AB is the same multiple of E, that KH is of F: But AB... 
