| Elias Loomis - Algebra - 1856 - 280 pages
...whose square is a'+2ab+b'. Hence we see that the square of a number composed of tens and units contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. Now the square of tens can give no significant figure in the first right-hand period ; the square of... | |
| Charles Davies - Arithmetic - 1856 - 450 pages
...When «o, decomposed, what IN its square equal to ' F 30 30 The square of a number is equal to ike 'square of the tens, plus twice the product of the...tens by the units, plus the square of the units. The same may be shown by a figure : Let the line AB represent the 3 tens or 30, and BC the six units. Let... | |
| Charles Davies - Algebra - 1857 - 408 pages
...have, N=a + b; whence, by squaring both members, N* = a* + 2a6 + b* : Hence, the square of a number is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. For example, 78 = 70 + 8, hence, (78)2 = (70)2 + 2 x 70 x 8 + (8)2 = 4900 + 1120 + 64 = 6084. 95i Let... | |
| Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...number of periods 66396 is two, the root will consist of two figures, 396 tens and units. Then 1296 = the square of - the tens plus twice the product of the tens 0 into the units, plus the square of the units. The square of tens is hundreds, and must therefore... | |
| Elias Loomis - Algebra - 1858 - 394 pages
...then, 841 is the square of a number composed of tens and units, it must contain the square of the lens, plus twice the product of the tens by the units, plus the square of the units. But these three terms are blended together in 841, and hence the peculiar difficulty in determining... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...periods C 6 3 9 6 is two, the root will consist of two figures, 3 9 (J tens and units. Then 1296 = the square of the tens plus twice the product of the tens 0 into the units, plus the square of the units. The square of tens is hundreds, and must therefore... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 456 pages
...of periods 66396 is two, the root will consist of two figures, 3 g (] tens and u»it.t. Then 1296 = the square of the tens plus twice the product of the tens 0 into the unit;!, plus the square of the units. The square of tens is hundreds, and must therefore... | |
| William Smyth - Algebra - 1858 - 344 pages
...= 2209. Thus the square of a number, consisting of units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The... | |
| Charles Davies - Algebra - 1860 - 412 pages
...have, N=a + b; whence, by squaring both members, N2 = a* + 2ab + b2 : Hence, the square of a number is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. For example, 78 = 70 + 8, hence, (78)2 = (70)2 + 2 X 70 X 8 + (8)2 = 4900 + 1120 + 64 = 6084. 95 1... | |
| Charles Davies - Algebra - 1860 - 330 pages
...2a;y + y~ - &• + (2x + y)y. That is, the number is equal to the square of the tens in its roots, plus twice the. product of the tens by the units, plus the square of the units. EXAMPLE. 1. Extract the square root of 6084. Since this number is composed of more than two places... | |
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