 | Benjamin Greenleaf - Arithmetic - 1846 - 206 pages
...contents ; or to three times the square of the radius of the segments base, add the square of its N* height ; then multiply the sum by the height, and the product by .5236 for the contents. 20. To find how large a cube may be cut from any given sphere, or be inscribed in it. RULE. Square... | |
 | Charles William Hackley - Geometry - 1847 - 248 pages
...Schol. to Prop. XIV., Sol. Geom.) RULE II. To three times the square of the radius of the segment-s base add the square of its height ; then multiply...by the height, and the product by •5236, for the content. ROLE III. When the segment has two bases, multiply the half sum of the parallel bases by the... | |
 | Benjamin Greenleaf - Arithmetic - 1847 - 232 pages
...or to three times the square of the radius of the segment's base, add the square of its N* Jieight ; then multiply the sum by the height, and the product by .5236 for the contents. 20. To find how large a cube may be cut from any given sphere, or be inscribed in it. RULE. Square... | |
 | Robert Burn - 1848 - 130 pages
...height, and this product by decimal '5236 ; or, To three times the square of the radius of the segment's base add the square of its height, then multiply the sum by the height and this product by '5236 for the content. 26. How is the capacity (or content ) of a Gamer chamber computed?... | |
 | John Bonnycastle - Geometry - 1848 - 320 pages
...x,.j XV7 X .52JO — , * ' \k I • v PROBLEM XIV. To jind the solidity of ike segment of a tphere* RULE.* To three times the square of the radius of its base add -f he square of its height; and this sum multiplied by the height, and the product again by .5236,... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...Rule. — To three times the square of the radius, ab, of its base, add the square of its height, bc ; then multiply the sum by the height, and the product by -5236, for the contents. E.ramp1e. — What is the solidity of the segment, adc, (of the sphere ec,) whose height, bc, is 8... | |
 | James Elliot - 1851 - 152 pages
...times the bulk of the earth. PROBLEM XII. To find the Solid Content of a Segment of a Sphere. RULE 1. To three times the square of the radius of its base add the square of its height. Multiply the sum by the height, and the product again by •5236 — . FORMULA. RULE 2. From three... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...And 2572 -4468 -4- 1728 = 1-48868 solid feet. To find the solidity of the segment of a sphere. — To three times the square of the radius of its base add the square of its height, and this sum multiplied by the height, and the product again by '5236, will give the solidity. Or,... | |
 | Charles Haynes Haswell - Engineering - 1851 - 346 pages
...by .5236, and the prodact is the solidity. To find the Solidity of a Spherical Segment— fig. 38. RULE. — To three times the square of the radius of its base ab, aiiu the square of its height cb ; then multiply this sum by the height. and the product by .5236.... | |
 | Septimus Norris - Locomotives - 1852 - 356 pages
...-5236 ; the product will be the solidityTo find the Solidity of a Spherical Segment, fig- 34RULE — To three times the square of the radius of its base...multiply the sum by the height, and the product by -5236To find the Solidity of a Spherical Zone or Frustum, fig- 35RULE — To the sum of the squares... | |
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... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents. 
