 | George E. Mercer - Arithmetic - 1909 - 312 pages
...of the means. Let the pupils test this equality with the proportions they have written and proved. Either extreme is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean. Hence, if any... | |
 | Jennings Cropper Wise - Artillery, Field and mountain - 1912 - 352 pages
...the means. In any proportion the product of the extremes is equal to the product of the means. Hence either extreme is equal to the product of the means divided by the other extreme, and either mean is equal to the product of the extremes divided by the other mean. Simple proportion... | |
 | George E. Mercer, Mabel Bonsall - Arithmetic - 1914 - 324 pages
...of the means. Let the pupils test this equality with the proportions they have written and proved. Either extreme is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean. Hence, if any... | |
 | Charles Ernest Chadsey - 1914 - 284 pages
...24-;-8, or ^, or 3. Either mean is equal to the product of the extremes divided by the other mean. Either extreme is equal to the product of the means divided by the other extreme. 1. 3 is to 7 as 6 is to what number? 2. 4 is to 5 as 8 is to what number? 3. 6 is to 8 as what number... | |
 | Measuring instruments - 1914 - 428 pages
...extreme and both means are known, the other extreme may be found by the following rule : Rule II. — Either extreme is equal to the product of the means divided by the other extreme. When stating a proportion in which one of the terms is unknown, represent the missing term by a letter,... | |
 | George Hervey Hallett, Robert Franklin Anderson - Algebra - 1917 - 432 pages
...product of the extremes divided by the other mean. 19. If four numbers are proportionals, prove that either extreme is equal to the product of the means divided by the other extreme. 20. If the product of two numbers is equal to the product of two other numbers, prove that a proportion... | |
 | United States. Army. Quartermaster Corps - 1930 - 1238 pages
...the means. In any proportion the product of the extremes is equal to the product of the means. Hence either extreme is equal to the product of the means divided by the other extreme, and either mean is equal to the product of the extremes divided by the other mean. Simple proportion... | |
 | United States. Army. Quartermaster Corps - 1930 - 1216 pages
...the means. In any proportion the product of the extremes is equal to the product of the means. Hence either extreme is equal to the product of the means divided by the other extreme, and either mean is equal to the product of the extremes divided by the other mean. Simple proportion... | |
 | Daniel Barnard Hagar - Arithmetic - 1871 - 352 pages
...2X6- But the factors 4 and 3 are the extremes, and the factors 6 and 2 are the means. Hence, also, 2. Either extreme is equal to the product of the means divided by the other extreme; and 3. Either mean is equal to the product of the extremes divided by the other mean. EXERCISES. 551.... | |
 | Stoddard A. Felter - Arithmetic - 1868 - 368 pages
...means, III. — Either mean is equal to the product of the extremes divided by the other mean. IV. Either extreme is equal to the product of the means divided by the other extreme. If 9 pounds of coffee cost $3.60, what will 11 Ib. cost? MODEL OPERATION. Extreme. Mean. Mean. Extreme.... | |
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That is, in any proportion either extreme ' is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean. 
