 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 490 pages
...in. Find volume of a similar cone of altitude (a) Sin. (6) 15 in. PROPOSITION XXXIII. THEOREM 689. The lateral area of a frustum of a cone of revolution is equal to one half the sum of the circumferences of its bases multiplied by its slant height. Given L the lateral... | |
 | George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...~ZX —i = ~a = "Ts = ~S' bJ § 612- QEDv' $ 7rr"a' rK a' r'3 a'3 s'3 PROPOSITION XXX. THEOREM 615. The lateral area of a frustum of a cone of revolution is equal to half the sum of the circumferences of its bases multiplied by the slant height. Given a frustum of... | |
 | George C. Shutts - 1913 - 212 pages
...indicated in § 630. What are the limits of S', p', and p'X e? 632. COR. I. The lateral area of a cylinder of revolution is equal to the product of the circumference of the base and an element, or the altitude, ie, S = 2 w rh. 633. COR. II. The lateral areas of similar cylinders... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Solid - 1917 - 220 pages
...the upper base of the frustum is the section made by the plane parallel to the base of the cone. 628. The lateral area of a frustum of a cone of revolution is equal to the product of the slant height and half the sum of the circumferences of its bases, or to the product of the slant height... | |
 | Ernst Rudolph Breslich - Logarithms - 1917 - 408 pages
...height and r the radius of the base. State in words the law expressed by this formula. 3. Show that the lateral area of a frustum of a cone of revolution is equal to the slant height multiplied by the length of a circle obtained by cutting the frustum by a plane at equal... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1918 - 486 pages
...in. Find volume of a similar cone of altitude (a) 8 in. (6) 15 in. PROPOSITION XXXIII. THEOREM 689. The lateral area of a frustum of a cone of revolution is equal to one half the sum of the circumferences of its bases multiplied by its slant height. Given L the lateral... | |
 | Arthur Horace Blanchard - Bridges - 1919 - 1720 pages
...the two bases of the frustum is called the SLANT HEIGHT of the frustum. The lateral surface of the frustum of a cone of revolution is equal to the product of half the sum of the circumferences of its bases multiplied by its slant height. The volume of the frustum... | |
 | Charles Austin Hobbs - Geometry, Solid - 1921 - 216 pages
...the lateral area and the distance of any element from the center of the base. Proposition 301 Theorem The lateral area of a frustum of a cone of revolution is equal to one half the product of the sum of the circumferences of its bases and its slant height. Let a frustum... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 484 pages
...... L' = £(p + P') x S. (Why?) [To be completed by the student. Use Theorem of Limits.] 690. COR. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. (RIR\ — ^—... | |
 | David Eugene Smith - Geometry, Solid - 1924 - 256 pages
...applies to a circular cone. §§ 155-159 109 Proposition 22. Lateral Area of a Frustum 158. Theorem. The lateral area of a frustum of a cone of revolution is half the product of the slant height and the sum of the circumferences of its bases. Given a frustum... | |
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The lateral area of a frustum of a cone of revolution is equal to one-half the sum of the circumferences of its bases multiplied by its slant height. Hyp. S is the lateral area, C and C... 
