 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...triangle is isosceles. First. Suppose the side AB—AC; we shall have .the angle C=R For, if the arc AD be drawn from the vertex A to the middle point D of the base, the two triangles ABD, A CD, will have all the sides of the one respectively equal to the corresponding sides of the other,... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...we shall have the angle C—B. For, if the arc AD be drawn from the vertex A to the middle point H of the base, the two triangles ABD, ACD, will have...respectively equal to the corresponding sides of the other, viz., AD common, BD=DC, and AB =AC : hence, by the last proposition, their angles will be equal; therefore,... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...isosceles. •First. Suppose the side AB = AC, we shall have the angle C — B. For, if the arc AD be drawn from the vertex A to the middle point D of...corresponding sides of the other, namely, AD common, BD = CD, and AB = AC ; hence, by the last proposition, their angles will be equal ; therefore B = 0.... | |
 | Peter Nicholson - Cabinetwork - 1856 - 518 pages
...equal. Let the side AB be equal to AC; then shall the angle C equal the angle B. For, suppose AD to be drawn from the vertex A to the middle point D, of the base BC ; then the two triangles ADB, ADC, will have the two sides AB, BD, of the one equal to the two sides... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...triangle is isosceles. First. Suppose the side AB=AC; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle point D of...respectively equal to the corresponding sides of the other, viz., AD common, BD=DC, and AB =AC : hence, by the last proposition, their angles will be equal; therefore,... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...be isosceles. First. Suppose the side AB = AC, we shall have the angle C — B. For, if the arc AD be drawn from the vertex A to the middle point D of...corresponding sides of the other, namely, AD common, BD = CD, and AB = AC ; hence, by the last proposition, their angles will be equal ; therefore B = C.... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...side AB is equal to the side AC ; then will the angle B be equal to the angle C. For, if the arc AD be drawn from the vertex A to the middle point, D,...corresponding sides of the other, namely, AD common, BD equal to DC, and AB equal to AC ; hence their angles must be equal ; consequently, the angles B... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...AB is equal to the side А С ; then will the angle В be equal to the angle C. For, if the arc AD be drawn from the vertex A to the middle point, D,...corresponding sides of the other, namely, AD common, В D equal to DC, and AB equal to А С ; hence their angles must be equal ; consequently, the angles... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...side AB is equal to the side AC ; then will the angle B be equal to the angle C. For, if the arc AD be drawn from the vertex A to the middle point, D,...corresponding sides of the other, namely, AD common, BD equal to DC, and AB equal to AC ; hence their angles must be equal ; consequently, the angles B... | |
 | Benjamin Greenleaf - Geometry - 1863 - 502 pages
...side AB is equal to the side AC ; then will the angle B be equal to the angle C. For, if the arc AD be drawn from the vertex A to the middle point, D, of the base,the two triangles ABD, ACD will have all the sides of the one respectively equal to the corresponding... | |
| |
For, if the arc AD be drawn from the vertex A to the middle point D of the base, the two triangles ABD, ACD will have all the sides of the one respectively equal to the corresponding sides of the other, namely, AD common, BD=DC, and AB= AC : hence by... 
