...x 5a26c = 35a362c. Again, 8a36c Hence, for the division of monomials we have the following RULE. I. Divide the coefficient of the dividend by the coefficient of the divisor. II. Write in the quotient, after the coefficient, all the letters common to the dividend and divisor,...

...for, ..... 7abx5a?-bc=35aWc. 50. Hence, for the division of monomials, we have the following RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor. II. Write in the quotient, after the co-efficient, all the letters common to the dividend and divisor,...

...or as both are polynomials. CASE I. 106. In this case, the dividend and divisor are both monomials. RULE. 1. Divide the coefficient of the dividend by the coefficient of the divisor. 2. Reject the letters common to both dividend and divisor when they have the same exponent; but when...

...one of the parts ? Ana. 3 1 c ; because 2 a times 3 bc ia 6 ab c. Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the letters of the divisor from the dividend. 3. Divide 16a6c by 4. 4. " 12aJc by 3a....

...„. , , Consequently, — «r~srr~ =7asc3. Whence, to divide one monomial quantity by another, Rule. Divide the coefficient of the dividend by the coefficient of the divisor ; the result is the coefficient of the quotient. To obtain the literal part of the quotient, 1st. "When...

...subtracted from its exponent. 50. Hence, for the division of monomials, we have the followmg RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor, for a new co-efficient. II. Write after this co-efficient, all the letters of the dividend, and affect each with an exponent...

...since 3X4a2=12a2. Hence we perceive, generally, that to obtain the coefficient of the quotient, we must divide the coefficient of the dividend by the coefficient of the divisor. Thus 24o2, divided by 6a2, produces 4. 67. If the division is not possible, we indicate it by writing...

...exponent of the divisor from the exponent of the dividend. (67.) Hence for the division of monomials, we have the following RULE. 1. Divide the coefficient...of the dividend by the coefficient of the divisor. 2. Subtract the exponents of the letters in the divisor from the exponents of the same letters in the...

...as both are polynomials. CASE I. 106. In this case, the dividend and divisor are both monomials. , . RULE. 1. Divide the coefficient of the dividend by the coefficient of the divisor. the same, subtract the exponent of the divisor from that of the dividend, and the remainder will be...

...equal to the difference of their squares. SECT. IV. D witton. 1. To divide one monomial by another, divide the coefficient of the dividend by the coefficient of the divisor for the coefficient of the quotient, and subjoin to it a fraction having for its numerator the letters...