 | Arthur Schultze - 1901 - 260 pages
...its sides 20 inches. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base 6 and altitude a, To prove area of R = ax 6. 'T Proof. Let U... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...other words, P contains the unit area bh times, or the measure of P is bh. THEOREM. The measure of the area of a rectangle is equal to the product of its base and its altitude. Or, more briefly, the area of a rectangle is equal to the product of its base and altitude.... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...factor S, We have R : R' = axb : a' X b'. II. 11. Therefore, etc. 150 PROPOSITION IV. — THEOREM. The area of a rectangle is equal to the product of its base by its altitude. Given. — Let R be a rectangle whose ba.se is b and altitude a. To Prove. —... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...and three or more sides that are parallelograms, is a Prism. TRIANGULAR PRISM RECTANGULAR PRISM 212. The area of a rectangle is equal to the product of its length and breadth. 213. A rectangular prism that is one unit high has a volume equal to the product... | |
 | Clara Avis Hart, Daniel D. Feldman - Geometry - 1912 - 504 pages
...of the Greeks, which was logical and deductive, even from its beginning. PROPOSITION I. THEOREM 475. The area of a rectangle is equal to the product of its base and its altitude. (See § 476.) BC V AD « Given rectangle ABCD, with base AD and altitude AB, and let... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 490 pages
...of its sides 20 in. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 347. The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove B = a x b. Proof. Let U be the unit of surface.... | |
 | William Benjamin Fite - Algebra - 1913 - 368 pages
...m2»3 + 5 mn* + и5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively, their combined... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry, Plane - 1913 - 328 pages
...of its sides 20 in. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 347. The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R — a X b. Proof. Let U be the unit of surface.... | |
 | William Benjamin Fite - Algebra - 1913 - 304 pages
...mW + 5 mw4 + w5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively, their combined... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Plane - 1913 - 376 pages
...called its dimensions. In Chapter IV (§ 181), we assumed (without proof) the well-known principle that the area of a rectangle is equal to the product of its two dimensions. Similarly, we shall now assume that the volume of a rectangular parallelepiped is equal... | |
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The area of a rectangle is equal to the product of its base and altitude. 
