| Thomas Tucker Smiley - 1830 - 188 pages
...first term ; the sum is the last term. 2. Add the first and last terms together, and multiply the sum by the number of terms ; and half the product will be the sum of all the terms. Case 2. When the first and last terms (or two extremes,) are given to find the... | |
| Daniel Adams - Arithmetic - 1830 - 280 pages
...Hence, when the extremes and the number of terms are given, to find the sum of all the terms,- — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
| Daniel Adams - Arithmetic - 1830 - 294 pages
...) Hence, when the extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ th'e sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
| Nathan Daboll - Arithmetic - 1831 - 246 pages
...Tiz. the first term, last term, number of terms, common difference, and sum of the series. HULK. — Multiply the sum of the extremes by the number of...EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 23, and the number of terms 1 1 ; required the sum of the series. 23+3=26 sum of the... | |
| William Kinne - Accounting - 1831 - 248 pages
...last term, and the number of terms being given, to find the sum of all the terms. RULE.—Multiply the sum of the extremes by the number of terms, and...answer. EXAMPLES. 1. The first term of an arithmetical progression is 1, the last term 21, the number of terms 11 ; required the sum of the series. 21 22... | |
| Ira Wanzer - Arithmetic - 1831 - 408 pages
...The extremes and the number of terms being given, to find the sum of all the termsofthe progression. RULE. — Multiply the sum of the extremes by the number of terms, and half of the product will be the sum of the series : Or, multiply one of those factors by half of the other,... | |
| Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...the number of terms are given, to find the sum of all the terms, Rule. Multiply the sum of the two extremes, by the number of terms, and half the product will be the answer. Or, multiply the sum of the two extremes by half the number of terms. * In any series of numbers, in... | |
| Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...Hence, when the extremes, and the number of terms are given, to find the sum of all the terms ; — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 3 and 373, and the number of terms 40, what... | |
| Francis Walkingame - 1833 - 204 pages
...— 1), and i=^nz. Case 1. The I wo extremes, and the number of terms being given, loßnd ihe sum. RULE. Multiply the sum of the extremes by the number...of terms, and half the product will be the answer.* (1) How many strokes does the hammer of a clock strike in 12 hours ft (2) A man bought 17 yards of... | |
| Daniel Adams - Arithmetic - 1833 - 268 pages
...) Hence, when the extremes and the member of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 6OS, ?nd the number of terms 151, what... | |
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