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" To find the area of a circle, multiply the square of the diameter by .7854. "
Elementary School Mathematics by Grades: Arithmetic, geometry, and algebra ... - Page 107
by William Estabrook Chancellor - 1902 - 176 pages
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The Iroquois Arithmetics: For School and Life, Book 3

Harry De Witt De Groat, Sidney Grant Firman, William A. Smith - Arithmetic - 1926 - 368 pages
...Multiply the square of the 567 radius by it. " = 12,474 The area of the pool is 12,474 sq. ft. Remember : To find the area of a circle, multiply the square of the radius by xFind the area of a circle whose radius is : 1. 7 ft. 3. 3 ft. 6 in. 5. 23 in. 7. 5 ft. 2....
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Brooklyn Daily Eagle Almanac, Volume 24

Almanacs, American - 1909 - 698 pages
...multiply the diameter by З.Ш6. For the diameter of a circle, multiply the circumference by .31381. For the area of a circle, multiply the square of the diameter by .7854. For the size of an equal square, multiply the diameter by .8862. For the surface of a ball, multiply...
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Project Scheduling Handbook

Jonathan F. Hutchings - Technology & Engineering - 2003 - 398 pages
...by 3.1416 (approx. 3 l/j). (b) The diameter of a circle, multiply the circumference by 0.31831. (c) The area of a circle, multiply the square of the diameter by 0.7854. (d) The area of a triangle, multiply the base by one half the perpendicular height. (e) The...
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Modern Carpentry and Building: Giving Methods of Obtaining the Various Cuts ...

William Allen Sylvester - Architecture, Domestic - 1896 - 264 pages
...Multiply the base by half of the perpendicular, or multiply half the base by the perpendicular Tojind the Area of a Circle. — Multiply the square of the diameter by .7854. To find the Circumference of <i Circle. — Multiply the diameter by 3.1416. To find /he Surface Area...
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The Iowa Normal Monthly, Volume 9

Education - 1885 - 612 pages
...experiment that .7854+ is that number. 1600 X .7854= 1246+, the area of the circle. Hence the rule — To find the area of a circle multiply the square of the diameter by .7854. 456 If an inside square is desired, connect the ends ol" the diameters with straight lines. It is evident...
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