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" In spherical triangles, whether right angled or oblique angled, the sines of the sides are proportional to the sines of the angles opposite to them. "
New American Practical Navigator - Page 292
1821
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Revue Semestrielle Des Publications Mathématiques, Volumes 7-8

Mathematics - 1899 - 744 pages
...36—38). K 20 f. J. JACK. A New Proof of the Formulae for RightAngled Spherical Triangles. Assuming that the sines of the sides are proportional to the sines of the opposite angles, the formulae for the rightangled spherical triangle are obtained by the aid of a slight modification...
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Plane and Spherical Trigonometry

Alfred Hix Welsh - Plane trigonometry - 1894 - 228 pages
...is middle. When complement of В is middle. § 3. PRINCIPLES. THEOREM I. In any spherical triangle, the sines of the sides are proportional to the sines of the opposite angles. Let ABC be a spherical triangle on a sphere whose centre is 0. From any point in О В let fall a perpendicular...
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A Treatise on Civil Engineering

William Macfarland Patton - Civil engineering - 1895 - 1710 pages
...the solution of plane triangles. The only relations that are necessary in most cases are, first, that the sides are proportional to the sines of the opposite angles, or, in case of a right-angle triangle, either side about the right angle is equal to the other side multiplied...
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A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - Geometry - 1896 - 274 pages
...fundamental formulae from a direct consideration of the solid angle itself. 3. In a spherical triangle, the sines of the sides are proportional to the sines of the opposite angles. Let ABC, Fig. 1, be a spherical triangle, 0 the center of the sphere. The angles of the triangle are...
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Proceedings of the Edinburgh Mathematical Society, Volumes 15-16

Edinburgh Mathematical Society - Electronic journals - 1897 - 316 pages
...New Proof of the Formulae for Right-Angled Spherical Triangles. By Professor JOHN JACK. It is assumed that the sines of the sides are proportional to the sines of the opposite angles. ACB (Fig. 9) is a spherical Д, with С a right angle. Produce AC, AB to D and E so that AD = AE =...
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Elements of Plane and Spherical Trigonometry

James William Nicholson - Trigonometry - 1898 - 204 pages
...in the form of a proportion, as shl о : sin b : : sin A : sin B. That is, in spherical triangles, the sines of the sides are proportional to the sines of the opposite angles, which property is called the Law of Sines. 143. Relation of the half of one angle to the three sides....
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Revue Semestrielle Des Publications Mathematiques, Volumes 7-8

1899 - 760 pages
...— 38). K 20 f. J. JACK. A New Proof of the Formulae for RightAngled Spherical Triangles. Assuming that the sines of the sides are proportional to the sines of the opposite angles , the formulae for the rightangled spherical triangle are obtained by the aid of a slight modification...
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Plane Trigonometry

Daniel Alexander Murray - 1906 - 466 pages
...sin A sin B . sin a _ sin b _ sin ct .... " sin ^~ sin .B~ sin C' W In words : /na spherical triangle the sines of the sides are proportional to the sines of the opposite angles. (Compare Plane Trigonometry, Art. 54, I.) B B. Derivation of the Law of Cosines. cos BC = cos CD cos...
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Spherical Trigonometry: For Colleges and Secondary Schools

Daniel Alexander Murray - Spherical trigonometry - 1908 - 132 pages
...shown that sin A sin B . sin a sin 6 sine sin A sin JB sin C (1) In words : In a spherical triangle the sines of the sides are proportional to the sines of the opposite angles. (Compare Plane Trigonometry, Art. 54, I.) and B. Derivation of the Law of Cosines. cos BC = cos CD...
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Plane [and Spherical] Trigonometry for Colleges and Secondary Schools

Daniel Alexander Murray - Plane trigonometry - 1908 - 358 pages
...that sin A sin B , sin a — sin b sine sin . I sin B sin C (1) In words : In a spherical triangle the sines of the sides are proportional to the sines of the opposite angles. (Compare Plane Trigonometry, Art. 54, I.) B. Derivation of the Law of Cosines. cos EC = cos (7Z) cos...
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