 | Emerson Elbridge White - Algebra - 1896 - 418 pages
...ad=b<; then c<= — . a = — : » = — , c = — : and d а с b hence either extreme of a proportion may be found by dividing the product of the means by the other extreme ; and either mean may be found by dividing the product of the extremes by the other mean.... | |
 | George Albert Wentworth - Algebra - 1898 - 428 pages
...г = 3 ' od Multiply by bd, ad = be. The equation ad = be gives a — — ib = — ; so that an ac extreme may be found by dividing the product of the means by the other extreme ; and a mean may be found by dividing the product of the extremes by the other mean.... | |
 | John Appley Ferrell - History - 1901 - 270 pages
...):2::20:4? NOTE. — Here we multiplied the two means together and divided by thi given extreme. Either extreme may be found by dividing the product of the means by the given extreme. (Commit.) 3. In the same proportion, suppose the second term missing. Find it. Process: 10: ( )::20:4?... | |
 | Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...PROPORTION. A missing mean may be found by dividing the product of the extremes by the given mean. A missing extreme may be found by dividing the product of the means by the given extreme. SIMPLE PROPORTION is an equality of two simple ratios, as, 9 Ib. : 1 8 Ib. : : 27 cents : 54 cents.... | |
 | John Marvin Colaw - Algebra - 1903 - 444 pages
...member of equation (1) by d, be a = — d Dividing each member by c, b = ^' c Hence, it is seen that an extreme may be found by dividing the product of the means by the other extreme, and a mean may be found by dividing the product of the extremes by the other mean. Have... | |
 | John Henry Moore - Business mathematics - 1904 - 404 pages
...ratios are equal, or that the product of the extremes is equal to the product of the means. 952. Hence, a missing extreme may be found by dividing the product of the means by the given extreme; and a missing mean may be found by dividing the product of the extremes by the given mean. ORAL EXERCISE... | |
 | George Albert Wentworth - Algebra - 1906 - 440 pages
...6 d Multiply by bd, ad = bс. The equation ad = be gives be ad a = - » о = — ; d с so that an extreme may be found by dividing the product of the means by the other extreme ; and a mean may be found by dividing the product of the extremes by the other mean.... | |
 | George Albert Wentworth - 1894 - 218 pages
...product of the means. For, if a : b = c : d, ac then 7 = - • bd Multiplying by bd, ad = be. 207. Hither extreme may be found by dividing the product of the means by the other extreme, and either mean may be found by dividing the product of the extremes by the other mean.... | |
 | Gustavus Sylvester Kimball - Business mathematics - 1911 - 444 pages
...Proportion /. A missing mean may be found by dividing the product of the extremes by the given mean. 2. A missing extreme may be found by dividing the product of the means by the given extreme. ORAL EXERCISE Find the missing term of the following proportions: 1. 16:4::8:? 4. ?: 32:: 2:16. 7.... | |
 | Charles W. Morey - Arithmetic - 1911 - 454 pages
...the means. Since the product of the means equals the product of the extremes, a missing extreme is found by dividing the product of the means by the given extreme. Thus, in 8 : 4 = 6 : ? 4 x 6 _ o ___„.; 12. Find the missing mean in 8 : ? = 6 : 3. 13. Tell how... | |
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If the means and one of the extremes are given, the other extreme may be found by dividing the product of the means by the given extreme. Thus, if... 
