 | Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination... | |
 | Thomas Tucker Smiley - 1830 - 188 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Daniel Adams - Arithmetic - 1830 - 280 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Arithmetic - 1831 - 198 pages
...and if the third term consist of several denominations, reduce it to its lowest denomination; then, Multiply the second and third terms together, and divide the product by the first term: the quotient will be the answer. Note. — The product of the second and third termsis of the... | |
 | Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...mentioned. After the statement is thus prepared, proceed by the following Ptule for Working the Question. 1. Multiply the second and third terms together, and divide the product by the first term- The quotient will be the answer to the question in the same name or denomination the second term... | |
 | Daniel Adams - Arithmetic - 1831 - 276 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...less, write the least of the other two given numbers for the third term, and the greater for the first. Multiply the second and third terms together, and...the product by the first, the quotient will be the answer. tion. PROPORTION. QUESTIONS FOR PRACTICE. 4. If 15 bushela of corn cost $7.50, what will 25... | |
 | Zadock Thompson - Arithmetic - 1832 - 182 pages
...less, write the least of the other two given numbers for the third term, and the greater for the first. Multiply the second and third terms together, and...the product by the first, the quotient will be the answer. NOTE. — Before stating the question, the first and third terms must be reduced to the same... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
