 Divide the first term of the remainder by twice the first term of the root, and add the quotient to the part of the root already found, and also to the trial-divisor.  Elementary Algebra - Page 243by Herbert Ellsworth Slaught, Nels Johann Lennes - 1915 - 373 pagesFull view - About this book
 | William James Milne - Algebra - 1908 - 476 pages
...a2, there is a remainder of 2 ab + b-. The second term of the root is known to be b, and that may be found by dividing the first term of the remainder by twice the part of the root already found. This divisor is called a trial divisor. Since 2 ab + № is equal to... | |
 | William James Milne - Algebra - 1911 - 378 pages
...a'2, there is a remainder of 2 ab + IP. The second term of the root is known to be ft, and that may be found by dividing the first term of the remainder by twice the part of the root already found. This divisor is called a trial divisor. Since '¿ ah + b2 is equal... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1912 - 300 pages
...a;)2, and subtracting (7) completes the subtraction of (4 x3 — 3 x2+2 x— 5)2. At each step the next term of the root is found by dividing the first term...the remainder by twice the first term of the root. Thus from (4) the third term of the root is 16 x4 -=- 2(4 *3) = 2x, corresponding to 2 ac -~ 2 a =... | |
 | George Wentworth, David Eugene Smith - Algebra - 1913 - 478 pages
...Find the principal square root of the first term, and subtract its square from the polynomial. Divide the first term of the remainder by twice the first term of the root, and write the quotient as the second term of the root. Multiply the sum of twice the first term and the... | |
 | George Wentworth, David Eugene Smith - Algebra - 1913 - 312 pages
...Find the principal square root of the first term, and subtract its square from the polynomial. Divide the first term of the remainder by twice the first term of the root, and write the quotient as the second term of the root. Multiply the sum of twice the first term and the... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1915 - 412 pages
...it as the first term of the root. (3) Subtract the square of this first term of the root. (4) Divide the first term of the remainder by twice the first term of the root, and write the quotient as the second term of the root. (5) Add this second term of the root to twice the... | |
 | Raymond Earl Manchester - Algebra - 1915 - 216 pages
...Squaring the quotient and subtracting this result from the expression, o*+4a3+6o2+4a+l 4a3+6a2+4a+l Dividing the first term of the remainder by twice the first term of the quotient, a4+4o3+6a2+4a+l \a2 +2a a4 2a'|4o3+6ai!+4a+l Bringing this term (2a) down as the second term... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1916 - 280 pages
...as tlie first term of the root. (3) Subtract the square of this first term of the root. (4) Divide the first term of the remainder by twice the first term of the root, and write the quotient as the second term of the root. (5) Add this second term of the root to twice the... | |
 | George William Myers, George Edward Atwood - Algebra - 1916 - 362 pages
...remainder is the product of twice the first term of the root and the second term. Therefore, 3. The second term of the root is found by dividing the first term of the remainder by 2a. 4. // we multiply the sum of 2a and b by b and subtract the result from 2ab+b2, the remainder is... | |
 | Ernst Rudolph Breslich - Logarithms - 1917 - 408 pages
...polynomial, is twice the product of the first term of the root by the next term. Therefore, the second term of the root is found by dividing the first term...the remainder by twice the first term of the root. 3. By adding 6, the second term of the root, to twice a, the first term, and then multiplying this... | |
| |
