...8 4 2936 Second Factor of Multiplier, 7 20552 Third Factor of Multiplier, 3 Product, 61656 = 61656 Several other sets of factors of 168 may be used,...set have been taken ; the last product will be the true product. 52. Multiply 743 by 42, ie by 7 and 6. Ans. 31206. 53. Multiply 3467 by 56. 54. 839 X...

...tons of coal, at $6 per ton, will cost $90. Hence, OBS. When the multiplier is a composite number, multiply the multiplicand by one of the factors of the multiplier. and this product by another, and so on till you have multiplied by all the factors. The last product will...

...6. 2936 2d Factor of Multiplier, 7 ' 20552 3d Factor of Multiplier, 3 Product, 61656 10276 6 61656 Several other sets of factors of 168 may be used,...manner. Hence, RULE. Multiply the multiplicand by one of t/te factors of the multiplier, and that product by another factor, and so on until all the factors...

...product by 3. The 3 last product is the answer. Hence, 270 shill. 44. To multiply by a composite number. Multiply the multiplicand by one of the factors of the multiplier, and this product by another, and so on till you have multiplied by all the factors. The last product will...

...Multiplier, 8 4 2936 2d Factor of Multiplier, 7 20562 3d Factor of Multiplier, 3 Product, 61656 61666 Several other sets of factors of 168 may be used,...similar example may be solved in like manner. Hence, BULB. Multiply the multiplicand by one of the factors of the multiplier, and that product by another...

...and 4 or 2, 2 and 3 are component parts or factors. 44. When the multiplier is a composite number, multiply the multiplicand by one of the factors of the multiplier and that product by another fatter, and so on until all the factors hav, been taken ; the last product will be the true product....

...2d Factor of Multiplier, 2936 7 20552 3d Factor of Multiplier, 3 10276 6 Product, • 61656 = 61656 Several other sets of factors of 168 may be used,...set have been taken ; the last product will be the true product. 49. Multiply $ 8.37 by 36. 50. Multiply $ 659 by 56. 51. Multiply 737 by 72. 52. Multiply...

...by 5 the factor 3, and the product thus arising by the other factor 5. Hence, the Ans. 300 pounds.. RULE. — Multiply the multiplicand by one of the factors of the multiplier, then this product by another, and so on, till all the factors have teen used. The last product will...

...used, and give the same product. Every similar example may be solved in like manner. Hence, " HULK. Multiply the multiplicand by one of the factors of...the factors in the set have been taken ; the last produci will be the true product. 49. Multiply $ 8.37 by 36. Ans. $ 301.32. 50. Multiply $ 659 by 56....

...367 4 = 61656 ei. What is a composite number? May a composite number have more than one Bet ofbctors? Several other sets of factors of 168 may be used,...similar example may be solved in like manner. Hence, Multiply the multiplicand by one of the factors of the multiplier, and that product by another factor,...