It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the first term. Shorter Course in Algebra - Page 170by George Albert Wentworth - 1886 - 165 pagesFull view - About this book
| George Albert Wentworth - Algebra - 1891 - 380 pages
...abx lacks only the third term, V, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing...second term by twice the square root of the first term. 282. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. To solve such an equation... | |
| George Albert Wentworth - Algebra - 1891 - 544 pages
...third term, è2, of being a perfect square. This third term is the square of the quotient obtained by dividing the second term by twice the square root of the first term. Every affected quadratic may be made to assume the form аV ± 2abx = с (§ 247). To solve such an... | |
| George Albert Wentworth - Algebra - 1892 - 342 pages
...square root of the first term. 226. Every affected quadratic may be made to assume the form of aV i 2 abx = c. The first step in the solution of such...obtained from dividing the second term by twice the squaie root of the first term. The second step is to extract the square root of each side of the resulting... | |
| George W. Lilley - Algebra - 1892 - 420 pages
...number by multiplication or division. Hence, General Method of Solving Quadratics. Add to each member the square of the quotient obtained from dividing the second term by twice the square root of the ßrst term. Then proceed as before. 5 3 35 EXAMPLE 2. Solve . . + - = - — 5 • X ~r~ vw *E — A... | |
| William James Milne - Algebra - 1892 - 370 pages
...сРя? + 2 abx + b2, it is evident that the third term, b2, is the square of the quotient obtained by dividing the second term by twice the square root of the first. 2. Solve the equation 3ж2 + 4 ж = 39. SOLUTION. 3а? + 4ж = 39 (1) (1)x3, 9 а? +12 х =117 (2)... | |
| George Albert Wentworth - Algebra - 1893 - 370 pages
...quadratic may be made to assume the form of aV ± 2 abx = c. To solve such an equation : The first step is to complete the square; that is, to add to each...square root of each side of the resulting equation. (1) Solve the equation 16a? + 5x — 3 = Чз? — x + 45. Wehave 16x2 + 5x-3 = Чx'-x + 45. Simplify,... | |
| George Albert Wentworth - Algebra - 1893 - 348 pages
...square root of the first term. 226. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. The first step in the solution of such...dividing the second term by twice the square root of thefirst term. The second step is to extract the square root of each side of the resulting equation.... | |
| George P. Lilley - Algebra - 1894 - 522 pages
...number by multiplication or division. Hence, General Method of Solving Quadratics. Add to each member the square of the quotient obtained from dividing...second term by twice the square root of the first term. Tlien proceed as before. 5 3 35 EXAMPLES. Solve — 4 +- = ^ Process. Free from fractions, 5 (x - 2)... | |
| George Albert Wentworth - Algebra - 1895 - 376 pages
...quadratic may be made to assume the form of с?з? ± 2abx = c. To solve such an equation : The first step is to complete the square ; that is, to add to each...the first term. The second step is to extract the squaío root of each side of the resulting equation. 18. 19. x 4 .í 6 1 x-2 - " х + Ъ 1 x-1 „3... | |
| Robert Griffith Hatfield - Architecture - 1895 - 774 pages
...of the above trinomial shows that the third term is equal to the square of the quotient obtained by dividing the second term by twice the square root of the first; or — (— y = V 2 a I Now a third term to the above binomial, equation (i 18.), may be obtained by... | |
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