 ... greater than the included angle of the second, then the third side of the first is greater than the third side of the second.  Elements of Geometry - Page 46by Andrew Wheeler Phillips, Irving Fisher - 1896Full view - About this book
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 486 pages
...practical problems, p. 289, No. 21.] PROPOSITION XXXI. THEOREM 132. If two triangles have two sides of the one equal respectively to two sides of the other,...is greater than the third side of the second. Given A ABC and A'B'C' with UNEQUAL LINES AND UNEQUAL ANGLES Proof STATEMENTS Apply A A'B'C' to A ABC so... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Solid - 1913 - 176 pages
...side is opposite the greater angle. 76. Corollary 1. If two triangles have two sides of the one equal to two sides of the other, but the included angle...first is greater than the third side of the second. 77. Corollary 2. If two oblique lines are drawn from a point C in a perpendicular CD to a line AB,... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Solid - 1913 - 184 pages
...angle. 76. Corollary 1. Iftwo triangles have two sides of the one equal to two sides of the other, l)nt the included angle of the first greater than the included...first is greater than the third side of the second. 77. Corollary 2. If two oblique lines are drawn from a point C in a perpendicular CD to a line AB,... | |
 | George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...the one equal respectively to two sides of the other, but the included angle of the first triangle greater than the included angle of the second, then...is greater than the third side of the second. Given the triangles ABC and XYZ, with CA equal to ZX and BC equal to YZ, but with the angle C greater than... | |
 | Walter Burton Ford, Earle Raymond Hedrick - Geometry, Modern - 1913 - 272 pages
...ABD AD = BD, and BD + DC>CB. Therefore AD + DC > CB ; that is, AC > CB. FIG. 49 Why? Post. 3 Ax. 9 greater than the included angle of the second, then...first is greater than the third side of the second. [HINT. In &ABC and A'B'C', \etAB=A'B', BG=B'C', and ZABC >£A'B>C>. Suppose AB < BC. Place A'B'C' on... | |
 | George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...the one equal respectively to two sides of the other, but the included angle of the first triangle greater than the included angle of the second, then...first is greater than the third side of the second. Y r Given the triangles ABC and XYZ, with CA equal to ZX and BC equal to YZ, but with the angle C greater... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Plane - 1913 - 378 pages
...ABD AD = BD, and BD + DC>CB. Therefore AD + DC > CB ; that is, AC > CB. FIG. 49 B Why? Post. 3 Ax. 9 greater than the included angle of the second, then...first is greater than the third side of the second. [HINT. In &ABC and A'B'C', let,AB=A'B', BC=B'C', and / ABC > Z A'B ' C". Suppose AB<BC. Place ABC on... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry, Plane - 1915 - 336 pages
...of one equal :r respectively to two sides of the other but the included angle of the first triangle greater than the included angle of the second, then...is greater than the third side of the second Given triangles DEF and ABC having DE = AB, EF = BC, To prove that DF>AC. Proof. Place AABC upon ADEF so... | |
 | John Wesley Young, Albert John Schwartz - Geometry, Modern - 1915 - 250 pages
...triangle are equal, respectively, to two sides of another, but the included angle of the first triangle is greater than the included angle of the second, then...first is greater than the third side of the second. c ci Fio. 88. Given the A ABC and A'B'C' with CA = C'A, CB = C'B', and Z ACE > ZA C'B'. To prove that... | |
 | Edward Rutledge Robbins - Geometry, Plane - 1915 - 280 pages
...sides of the other, but the included angle in the first greater than the included angle in the second, the third side of the first is greater than the third side of the second. Given: A ABC, DEF; AB = DE; BC=EF; Z ABC > Z E. To Prove : AC> DF. Proof : Place the A DEF upon A ABC so that... | |
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