 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...the first rectangle is 20 sq. ft., as that has not yet been established.] PROPOSITION V. THEOREM 586. The area of a rectangle is equal to the product of its base and altitude. AD Let ABCD be any rectangle. To Prove ABCD = ax 6. Proof. Let the square U, each... | |
 | Samuel Wesley Baird - Arithmetic - 1901 - 174 pages
...retaining the same base and altitude. Rhomboid Area=6 sq. in. 3 in. 3in. s Area = 6 sq. in. 3in. As the area of a rectangle is equal to the product of its base and altitude, this is also the area of the rhomboid. PRACTICAL MENSUKATION 125 LESSON 111 1. What... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...Find the ratio of the areas of the two rectangles. AREAS OF POLYGONS PROPOSITION III. THEOKEM 339. The area of a rectangle is equal to the product of its base and altitude. 1 u Hyp. R is a rectangle with base b and altitude a. To prove area of R = ax b.... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...Find the ratio of the areas of the two rectangles. 166 AREAS OF POLYGONS PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base b and altitude a. To prove area of R = ax... | |
 | Arthur Schultze - 1901 - 260 pages
...its sides 20 inches. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base 6 and altitude a, To prove area of R = ax... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...and three or more sides that are parallelograms, is a Prism. TRIANGULAR PRISM RECTANGULAR PRISM 212. The area of a rectangle is equal to the product of its length and breadth. 213. A rectangular prism that is one unit high has a volume equal to the product... | |
 | John Marvin Colaw - Algebra - 1903 - 444 pages
...equal to the subtrahend. 58. The product divided by the multiplier is equal to the multiplicand. 59. The area of a rectangle is equal to the product of its base by its altitude. 60. The area of a circle is equal to the square of its radius multiplied by w. 61. The square... | |
 | Alan Sanders - Geometry - 1903 - 396 pages
...the first rectangle is 20 sq. ft., as that has not yet been established.] PROPOSITION V. THEOREM 586. The area of a rectangle is equal to the product of its base and altitude. BC D Let ABCD be any rectangle. To Prove ABCD = axb. Proof. Let the square U, each... | |
 | John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1903 - 408 pages
...64. The number of square units in a rectangle is called its area. From the above it is evident that the area of a rectangle is equal to the product of its length and width. The length and width are called the two dimensions of the rectangle. 65. The area... | |
 | American School (Chicago, Ill.) - Engineering - 1903 - 390 pages
...that is, B ~ tf Multiplying equations (1) and (2), we have A a X b B ~ a' x V THEOREM 1 XIII. 1 94. The area of a rectangle is equal to the product of its base and altitude. iL Let a and b be the numerical measures of the altitude and base of the rectangle... | |
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The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. 
