...х - 25 z10 + 2 а? + 7 z6 - 8 х4 - 3 х8 - 15 ж8 + 10 хг - 5 а; -25 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have x10 — x9 + 2 xe — x6 — 5 x* + 3 z9...

...2a2 + ab - 662, Ans. have 2aJ + 06 - 66Z. From this example we derive the following RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. m2 + 2mn + w2, ^4ns. m2 — 2mn + n2 m'1 5. 6. a4 + rt'6 + a262 x*-x« + z4 -...

...Multiplication of Polynomials. The terms of each polynomial having been arranged, we proceed to multiply each term of the multiplicand by each term of the multiplier, and take the sum of the results. The reason for this is made clear by taking two polynomials, a + b and...

...article is derived the following principle for multiplying a multinomial by a multinomial: Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. Ex. l. Multiply -3a + 2& by 2a-36. We have -36x26 (1) = - 6 a2...

...bm + bn + bp + cm + cn + cp. 102. To Find the Product of Two Polynomials, therefore, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. In multiplying polynomials, it is a convenient arrangement to write the multiplier...

...times a + 6 = a'2 + a6 6 times a + b = ab + Ift (a + 6) times (a + 6) = a2 + 2 ab + 6" RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 3. 2 ab - 3 ca? x — y ;26'2- lOa6c-Sc2 & Multiply : 4. x + ybyx + y. 17....

...No. 9. Algebraic Multiplication (Continued) To multiply one compound expression by another, multiply each term of the multiplicand by each term of the multiplier, and add results for the complete answer. To find the product of a + b and c + d. (o+6) x(c + d) = (a + 6) (c+d)...

...2\3ab-4:a(c-2b')l. 23. 7ac-2{2c(a-3&)-3(5c-2Z»)a|. 79. To multiply one polynomial by another, Multiply each term of the multiplicand by each term of the multiplier, and add the resulting products. Proof. Let x + y + z be the multiplicand, and a + b the multiplier ; then by...

...polynomial. RULE. — Arrange the multiplicand and multiplier with reference to the same letter. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 2- 3a263+ 2o64 +26* b3 — 6a464+ - 8a464+ a —b +2 c +x -3 ac —...

...This example illustrates the following method of multiplying a multinomial by a multinomial : Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. In general, (a + 6)(c + d- e) = a(c + d- e) + b(c + d- e) = ac...