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" LENGTH 12 inches (in.) = 1 foot (ft.) 3 feet = 1 yard (yd.) 5| yards = 1 rod (rd.) 320 rods = 1 mile (mi.) 1 mile = 1,760 yd. "
Everyday Arithmetic - Page 312
by Franklin Sherman Hoyt, Harriet E. Peet - 1920
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Fish's Arithmetic Number Two: Oral and Written, Upon the Inductive ..., Book 2

Daniel W. Fish - Arithmetic - 1883 - 364 pages
...175. Linear 01 line measures are used in measuring lines and distances. TABLE OF UNITS. EQUIVALENTS. 12 Inches (in.) = 1 Foot, . . . ft. 3 Feet = 1 Yard, . . . yd. 5\ Yards, or 16J ft. = 1 Bod, . . . rd. 820 Rods = 1 Mile, . . . mi. 1 mi. = f 63360 in. 5280 ft. 1760 yd. 320 rd....
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Fish's Arithmetic Number One: Oral and Written ...

Daniel W. Fish - Arithmetic - 1883 - 186 pages
...MEASURES OF EXTENSION. 99. Linear or Line Measures are used in measuring lines and distances. TABLE. 12 Inches (in.) = 1 Foot, . . ft. 3 Feet = 1 Yard, . . yd. 5£ Yards, or ) 4 Feet [= 1Rod' • • "*• 320 Rods = 1 Mile, . . mi. 100. Surface or Square Measure is used in...
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Sadlers̓ Hand-book of Arithmetic: Containing the Principles of Arithmetic ...

Warren H. Sadler, William Russell Will - Arithmetic - 1885 - 422 pages
...Linear or Long Measure is used in measuring lengths, breadths, depths, heights, or distances. Table. 12 inches [in.] = 1 foot [ft.] 3 feet =1 yard [yd.] 5' yards = 1 rod [rd.] 320 rods = 1 mile [mi.] Massachusetts. 1 Pennjfytvanifi. Rhode Jslanä. COMMODITIES....
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Arithmetic

A G. Blake - 1885 - 218 pages
...Vя11)8. oz. Ibs. oz. dr. 3 • 7 . II (12) 20 . 8 . 5 a . 18 • !3 3 , 8 . II measure of Length. Marked. 12 inches (in») = 1 foot ft. 3 feet = 1 yard yd. 5 k yards = 1 rod, perch, or pole per. or po. 4 poles =! 32 yards = 1 chain ch. 40 poles = 1 furlong...
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Standard Elementary Arithmetic: Combining Oral and Written Exercises

Edward Sylvester Ellis - Arithmetic - 1886 - 200 pages
...LINEAR OR LONG MEASURE. ART. 156.—Linear or Long measure is used in measuring lengths and distances. 12 inches (in.) =1 foot, ft. 3 feet = 1 yard, yd. 5£ yards, or I6i feet = 1 rod, rd. 320 rods = 1 mile, mi. 1. How many rods in 2 mi.? 2. How many inches in 2 yds.?...
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Complete Arithmetic: Elements and Commercial. New Series

Christian Brothers - Arithmetic - 1888 - 484 pages
...is the yard. It is equal to f MMi °t the length of a pendulum vibrating seconds, at London. TABLE. 12 inches (in.) = 1 foot ft. 3 feet = 1 yard yd. 5| yards, or 16| feet = 1 rod rd. 320 rods = 1 mile m. OTHER DENOMINATIONS. 12 lines = 1 inch. 3 sizes = 1 inch (shoemaker's). 4 inches = 1 hand...
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Exercises in Arithmetic

George Albert Wentworth, George Anthony Hill - Arithmetic - 1887 - 448 pages
...length in feet at 30° of a bar whose length atO°is 10* feet? CHAPTER IV. COMMON MEASURES. TABLES. I. LENGTH. 12 inches (in.) = 1 foot (ft.). 3 feet = 1 yard (yd.). 5J yards, or 16J feet = 1 rod (rd.). 320 rods, 1760 yards, }lmil,mi)• or 5280 feet J Measures sometimes...
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Proceedings of the Edinburgh Mathematical Society, Volumes 5-6

Edinburgh Mathematical Society - Mathematics - 1887 - 316 pages
...hundredweight (cwt.) 20 hundredweights = 1 ton. [7000 grains (gr. ) = 1 pound. 14 pounds = 1 stone (8t. )] Length. 12 inches (in.) = 1 foot (ft.) 3 feet = 1 yard (yd.) 1760 yards = 1 mile (ml.) [22 yards = l chain (cft.) = 100 links (Ik.)] Surface. 144 or 12 x 12 square...
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A Grammar School Arithmetic

George Albert Wentworth - Arithmetic - 1888 - 378 pages
...reduction descending ; and 24 inches = 2 feet is an example of reduction ascending. UNITS OF LENGTH. 145. 12 inches (in.) = 1 foot (ft.). 3 feet = 1 yard (yd.). 5£ yards, or 16{ feet, = 1 rod (rd.). 320 rods, 1760 yards, or 5280 feet, = 1 mile (mi.). NOTE. A line = ^ in. ; a barleycorn = J in. ; a hand (used...
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Second Lessons in Arithmetic: An Intellectual Written Arithmetic Upon the ...

Henry Nathan Wheeler - Arithmetic - 1888 - 312 pages
...$4.866 i. FRENCH MONEY. 100 centimes = 1 franc ($0.193). GERMAN MONEY. 100 pfennigs = 1 mark ($0.238). LENGTH. 12 inches (in.) = 1 foot (ft.). 3 feet = 1 yard (yd.). 16J feet or ) , . , , , _f , >- =1 rod (rd.). 5£ yards ) 320 rods or) . .. , . rr>orv ,. f = 1 nllle...
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