 | William Smyth - Algebra - 1855 - 370 pages
...and C in 60 minutes, and the three together in 10 minutes. 7. It is required to divide the number 72 into four such parts, that if the first part be increased by 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
 | Elias Loomis - Algebra - 1856 - 280 pages
...which equation we find z=24, Ans. Prob. 45. Divide the number 45 into four such parts that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. In solving examples of this kind, several unknown quantities are usually introduced,... | |
 | 1856 - 428 pages
...What is the fraction ? Ans. /, . Prob. 49. Divide the number 90 into 4 such parts, that the first is increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. Ans. 18, 22, 10, and 40. Prcb. 50. Find three numbers, such that the first with... | |
 | Charles Davies - Algebra - 1857 - 262 pages
...the conditions of the problem, 1120 + 7ж -640+ 12ж — 5ж= -480 x = 96 .'. value, £4.16«. 17. To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
 | William Smyth - Algebra - 1858 - 344 pages
...and C in 60 minutes, and the three together in 10 minutes. 7. It is required to divide the number 72 into four such parts, that if the first part be increased by 5, the second part diminished by 5, the third part multiplied by 5, and the fourth part divided by... | |
 | Charles Davies - Algebra - 1859 - 324 pages
...we thus find the value of y. PROBLEMS. 1. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall be equal each to each. This problem may be easily solved by introducing a new unknown quantity.... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...end of 7 months, and r&3eived only £2 13s. 4d. and his livery; what was its value? Ans. £4 16*. 17. To divide the number 90 into four such parts' that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...x, y and i. Ans. x = 12, yr= 20, 2 = 30. 4. Divide the number 90 into four such parts that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall be equal each to each. This problem may be easily solved by introducing a new uuknown quantity.... | |
 | Isaac Todhunter - Algebra - 1863 - 302 pages
...could it be filled by the other alone? 11. Divide the number 90 into four parts such that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2 may all be equal. 12. A person bought 30 pounds of sugar of two different sorts, and paid for it 19s.... | |
 | Robert Wallace - 1870 - 164 pages
...difference, sum, and product are to each other as the numbers 2, 3, and 5 respectively ? Ans. 10 and 2. 20. Divide the number 90 into four such parts that if the first be increased by 2, the second diminished 2, the third multiplied by 2, and the fourth divided by 2,... | |
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Divide the number 90 into 4 such parts, that the . first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. 
