 | Samuel Webber - Arithmetic - 1812 - 260 pages
...miles. PROBLEM 3. Given the first term, the last term, and the common difference^ to find the number of terms. % RULE.* Divide the difference of the extremes by the common dlf* By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...A. 12. Hence, When the Extremes and Common Difference aregieeii, toßrul the Number of Term» ;— Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 17. If the extremes be 3 and 45, and the common difference 6, what is lh* •umber... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...debt. PROBLEM HI. / ' Giyeji the first term, last term, aad common difference, to' find the number of terms. RULE. Divide the difference of the extremes...difference, and the quotient increased by 1 is the number of terms. ; EXAMPLES. 1. If the extremes be 3 and 45, and the common difference 2 ; what is the number... | |
 | Arithmetic - 1818 - 264 pages
...journey 180 miles. PROBLEM III. The two extremes and the common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common diffenence, and the quotient, increased by 1, is the number of term* inquired. EXAMPLES. 1. If the... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...the. jírst term, the last term, and the common différente to find the number of term», . , , ¡ \. RULE.— "Divide the difference of the extremes by...the common difference, and the quotient increased by one is the number of terms required. , . , .EXAMPLES. 1. If the extremes, be 3 and 19, «nd the common... | |
 | Nicolas Pike - Arithmetic - 1822 - 536 pages
...1+2+3+4+5+6+7+0=— =36. 2 PROBLEM III. . . • Given the extremes and the common difference, to find ifie number of terms. RULE.* Divide the difference of the extremes...common difference, and the quotient increased by 1 will be the number of terms required. EXAMPLES. 1st. The extremes are 3 and 39, and the common difference... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...years. Problem III. The first term, the last term, and common difference given, to find the number of terms. RULE.! — Divide the difference of the...difference, and the quotient, increased by 1, is the number of terms required. Examples. 1. The extremes are 2 and 53, and the common difference 3 ; what is the... | |
 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...basket ? A. 7042 miles. PROBLEM II. — Given the extremes and common difference to find the number of terms. RULE. — Divide the difference of the extremes,...difference, and the quotient increased by 1, is the answer. EXAMPLES. — If the extremes be 3 and 45, and the common difference 6 ; what is the number... | |
 | B. M. Tyler - Arithmetic - 1827 - 308 pages
...and the last 70; — how many miles does he increase daily ? Ans. 7. PROBLEM IV. To find the number of terms. • RULE. Divide the difference of the extremes by the common difference, and add one to the quotient. Illustration. — The greatest term is made up of the common difference added... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...455 miles. PROB. III. — Given the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of the extremes...the common difference, and the quotient increased by one, is the number of terms. Examples. 1. Let the extremes be 5 and 53, and the common difference 6... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
