 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...54.299 rods. 307. To find the area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the other 12.25, and the perpendicular... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...54.299 rods. 307. To find (he. area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the other 12.25, and the perpendicular... | |
 | John Bennett (Engineer) - 1833 - 488 pages
...MEASURER, Practical. I'RUBLEM V. To find the area of a quadrangle ABCD, having two parellel sides AB, DC. B RULE. Multiply half the sum of the parallel sides by the perpendicular between them ; and the product will give the area. EXAMPLE. Let the parallel sides AB, DC, and the... | |
 | William Galbraith - Astronomy - 1834 - 454 pages
...logarithms. 3. Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half the sum of the parallel sides by the perpendicular distance between them. fi. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...? Ans. 700-99. PROBLEM XIII. To find the area of a Trapezoid RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.* 1. Let A BCD be a trapezoid, the side AB = r — -¡ i 40, D С = 25, С D = \ / (\... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...the area? Ans., 24 chains. To find the area of a trapczoid. ROLE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. What is the area of a piece of land that is 30 chains long, 20 chains wide at one end, and 18 chains... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...area. Am. 700.99. PROBLEM XIII. To find the area of a Trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.* 1. Let ABCD be a trapezoid, the side AB=40, DC = 25, CP = 18, required the area. 40... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...hypotenuse. ^ 16s + 122 = 20, the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half the sum of the parallel sides by the...distance between them, and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides being 25 and 33 and the perpendicular... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...54.299 rods. 307. To find IKt etna «/ a trapezoid. (65) Itu ir. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the ares. 1. One of the two parallel •ides of a trapezoid is 7.5 chairs, and the other 12.25, and the... | |
 | Charles Davies - Geometrical drawing - 1840 - 262 pages
...the breadth of the Ans. 77,8875 feet. PROBLEM VI. 13. To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : — the quotient will be the area. EXAMPLES. DC 1. Required the area... | |
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Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
