 The area of a zone is equal to the product of its altitude by the circumference of a great circle.  Solid Geometry - Page 447by Clara Avis Hart, Daniel D. Feldman, Virgil Snyder - 1912 - 188 pagesFull view - About this book
 | John H. Williams, Kenneth P. Williams - Geometry, Solid - 1916 - 184 pages
...the sphere the zone is called a zone of one base. Arc AB generates a zone of one base. 723. THEOREM. The area of a zone is equal to the product of its altitude by the circumference of a great circle. Let s denote the area and h the altitude of the zone generated... | |
 | William Betz, Harrison Emmett Webb - Geometry, Solid - 1916 - 214 pages
...applied to a right circular cylinder we have the result : The lateral area of a right circular cylinder is equal to the product of its altitude and the circumference of the base. In symbols, if I = lateral area, r = radius of the base, & = altitude, / = 639 . A second... | |
 | William Betz - Geometry - 1916 - 536 pages
...applied to a right circular cylinder we have the result: The lateral area of a right circular cylinder is equal to the product of its altitude and the circumference of the base. In symbols, if I — lateral area, r = radius of the base, h = altitude, 1 = 2 -rrrh. 639.... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Solid - 1917 - 220 pages
...spheres v^. , S _ 4 TTr* _ T2 d'z ' a S° tf ™ 4^ - pa ' 714. COR. 2. The area of a zone z's e^waZ to the product of its altitude and the circumference of a great circle of the sphere. Hence, if S denotes the area and h the altitude of the zone, S = 2 irrh. 715. Formula... | |
 | Eugene Randolph Smith, William Henry Metzler - Geometry, Solid - 1918 - 232 pages
...It may be called a proposition, but in any case it is assumed here without proof. 283. Theorem XVII. The area of a zone is equal to the product of its altitude and the circumference of a great circle- Area = 2 -rrrh. For, if a broken line is inscribed, as explained in § 282, the area generated by any... | |
 | Claude Irwin Palmer - Geometry, Solid - 1918 - 192 pages
...variables that are always equal. § 644 322 653. Theorem. The lateral area of a right circular cylinder is equal to the product of its altitude and the circumference of its base. That is, S = ch, where S denotes lateral area, c circumference of base, and h altitude. EXERCISES... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry - 1918 - 460 pages
...always equal. § 644 .-.S = pe. §485(1) 653. Theorem. The lateral area of a right circular cylinder is equal to the product of its altitude and the circumference of its base. That is, S = ch, where S denotes lateral area, c circumference of base, and h altitude. EXERCISES... | |
 | Charles Austin Hobbs - Geometry, Solid - 1921 - 216 pages
...in a lune is equal to twice the number of degrees in the angle of the lune. Proposition 342 Theorem The area of a zone is equal to the product of its altitude and the circumference of a great circle. Use a method of proof similar to that used in Prop. 341. COR. I. Let Z denote the area of a zone, h... | |
 | Robert Franklin Anderson - Arithmetic - 1921 - 348 pages
...equal to the product of its altitude and the perimeter of the base. 2. The lateral area of a cylinder is equal to the product of its altitude and the circumference of the base. Formulae. If H is the number of units in the altitude of a prism (see page 250) and P the... | |
 | Baltimore (Md.). Department of Education - Mathematics - 1924 - 182 pages
...lune in spherical degrees is equal to twice the number of angular degrees in the angle of the lune. 3. The area of a zone is equal to the product of its altitude and the circumference of a great circle of the sphere. 4. The volume of a spherical sector is equal to one third the product of its radius... | |
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