 | Andrew Jackson Rickoff - Arithmetic - 1886 - 688 pages
...product. Thus, In this case we see that 365. The square of 43 is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. v- Q It may be shown that the same is true of any number. Raise the following numbers to the second... | |
 | Charles Scott Venable - Arithmetic - 1888 - 402 pages
...the third power. III. The square of a number containing tens is equal to the square of the tens plus twice the product of the tens by the units plus the square of the units. IV. The cube of a number containing tens and units equals the cube of the tens plus three times the... | |
 | Andrew Jackson Rickoff - 1888 - 464 pages
...product. Thus, in this case we see that 365. The square of 43 is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. It may be shown that the same is true of any number. Raise the following numbers to the second power,... | |
 | Charles Davies - Algebra - 1889 - 330 pages
...found the tens, we subtract their square from the given number, and the remainder will be made up of twice the product of the tens by the units plus the square of the units. To find the units, divide -the remainder by twice the tens, and the quotient will be the units, or... | |
 | John Bernard Clarke - Algebra - 1889 - 566 pages
...from the remainder that part of the square of the tens plus the units not already subtracted, viz., twice the product of the tens by the units, plus the square of the units, on the principle indicated in (218). We thus have the following RULE.—Separate the given number into... | |
 | Charles Austin Hobbs - Arithmetic - 1889 - 370 pages
...general, the square of any number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. I. Find the square root of 5329. 5329(70 + 3 = 73 Since the number consists 490O of two periods, the... | |
 | Webster Wells - Arithmetic - 1893 - 382 pages
...x 4 + 42. That is, the square of any number of two figures is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. 198. It follows from Art. 197 that 742 - 702 = 2 x 70 x 4 + 42 = (2 x 70 + 4) x 4. That is, if from... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...figure of the root must be 2. Now, as the number 576 equals the square of the tens of the root, plus twice the product of the tens by the units plus the square of the units, if we subtract from 576 the square of the tens of the root, that is 203, or 400, the remainder, 176,... | |
 | Charles Edward White - Arithmetic - 1897 - 312 pages
...PRINCIPLE. — The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. FORMULA. — Tens2 + 2 x tens x units -f- units2. Separate the following into tens and units, and-... | |
 | Charles Edward White - Arithmetic - 1901 - 472 pages
...PRINCIPLE. — The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. FORMULA. — Tens 2 + 2 x tens x units + units 2 . Separate the following into tens and units, and... | |
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The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. 
