 In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which...  The Elements of Algebra - Page 73by Elias Loomis - 1856 - 268 pagesFull view - About this book
 | Edward Olney - Algebra - 1880 - 354 pages
...completed. 84. Prob. — To multiply two factors together when one or both are polynomials. R ULE. — MULTIPLY EACH TERM OF THE MULTIPLICAND BY EACH TERM OF THE MULTIPLIER, AND ADD THE PRODUCTS. DEM. — Thus, if any quantity is to be multiplied by a + Ъ — e, if wo take it a times... | |
 | Edward Olney - Algebra - 1881 - 254 pages
...the three partial products I have 15z 2 — z—8z 2 , which is 5x + 3y-2z times 3z— 2y+4z. . 28. RULE. — Multiply each term of the multiplicand by each term of the multiplier, and add the products. 2. Multiply 3a 3 5-2«5 3 +53 by2a5+52. OPERATION. + 3a 3 b 3 — Prod., 6a35 2 +3a 3... | |
 | Edward Olney - Algebra - 1881 - 506 pages
...by Vtf. Prod., a1**. 92. Prob.— To multiply two factors together when one or both are polynomials. Rule. — Multiply each term of the multiplicand by each term of the multiplier, and add the products. Demonstration. — Thus, if any quantity is to he multiplied by a + &— c, if we take... | |
 | Simon Newcomb - Algebra - 1882 - 302 pages
...result as before. We have therefore the following rule for multiplying one polynomial by another. 119. RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the products with their proper algebraic signs. EXERCISES. 1. (m - n) (p - q). Solution, (m — n)p... | |
 | Edwin Pliny Seaver, George Augustus Walton - Algebra - 1881 - 304 pages
...arrangement. 107. From these examples may be derived a Rule for the Multiplication of Polynomials. Multiply each term of the multiplicand by each term of the multiplier, and add the results. 108. Exercises. 267. Multiply 1 — 2a* + 36ar ! by3n. 268. Multiply 2 ax + by — cz... | |
 | Simon Newcomb - Algebra - 1884 - 572 pages
...get the same result as before. We have therefore the following rule for multiplying aggregates : 78. RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the products wi-th their proper algebraic signs. EXERCISES. 1. (a + b) (2a - 5»2 — 2§w8). 2. (a... | |
 | James Bates Thomson - Algebra - 1884 - 334 pages
...98. The various principles developed in the preceding cases, may be summed up in one GENERAL RULE. r Multiply each term of the multiplicand by each term of the multiplier, giving each product its proper sign, and each letter its proper exponent. The sum of the partial products... | |
 | Webster Wells - 1885 - 368 pages
...d was ac — be — aci + 6d. We have then the following rule for the product of two polynomials : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 1. Multiply Зa — 26 by 2a — 56. In accordance with the rule, we... | |
 | Webster Wells - Algebra - 1885 - 324 pages
...d was аc — be — ad + &d. We have then the following rule for the product of two polynomials : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. EXAMPLES. 1. Multiply За — 2& by 2 а — 5&. In accordance with the rule,... | |
 | Edward Brooks - Algebra - 1888 - 190 pages
...Adding the partial 2a2 — ab products, we have 2a2+3a6- 262. Therefore, etc. +4a6-26' 2a2 + 3a6-26« Rule. — Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. a — 6 a +6 a2-a6 +a6-62 a3 -62 (6.) an-6" a2-6' a8 -62 an+Ja"68-a26"+6"+3 7.... | |
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