| Education - 1899 - 884 pages
[ Sorry, this page's content is restricted ] | |
| Charles Hamilton Ashton, Walter Randall Marsh - Trigonometry - 1900 - 184 pages
...opposite parts. Then the ten formulas obtained above may be condensed into the two following rules : **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines... | |
| Charles Hamilton Ashton, Walter Randall Marsh - Trigonometry - 1902 - 186 pages
...opposite parts. Then the ten formulas obtained above may be condensed into the two following rules : **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines... | |
| George Albert Wentworth - Trigonometry - 1902 - 256 pages
...middle part is equal to the product of the tangents of the Adjacent parts. RULE II. The sine of any **middle part is equal to the product of the cosines of the** opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
| George Albert Wentworth - Trigonometry - 1903 - 346 pages
...middle part is equal to the product of the tangents of the &Ajacent parts. RULE II. The sine of any **middle part is equal to the product of the cosines of the** opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
| George Albert Wentworth, George Anthony Hill - Logarithms - 1903 - 348 pages
...middle part is equal to the product of the tangents of the Adjacent parts. RULE II. The sine of any **middle part is equal to the product of the cosines of the** opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
| Daniel Alexander Murray - 1906 - 466 pages
...the middle part, and o, 6, are opposite parts. Napier's rules of circular parts are as follows : I. **The sine of the middle part is equal to the product of the** tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Daniel Alexander Murray - Plane trigonometry - 1908 - 358 pages
...adjacent parts, thus getting ten sets in all. Napier'' s rules of circular parts are as follows : I. **The sine of the middle part is equal to the product of the** tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Daniel Alexander Murray - Spherical trigonometry - 1908 - 132 pages
...the middle part, and a, b, are opposite parts. Napier's rules of circular parts are as follows : I. **The sine of the middle part is equal to the product of the** tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Levi Leonard Conant - Trigonometry - 1909 - 320 pages
...the opposite parts. Napier's rules for the solution of spherical right triangles are as follows : 1. **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. 2. The sine of the middle part is equal to the product of the cosines... | |
| |