| Benjamin Peirce - Trigonometry - 1852 - 410 pages
...sine of the middle part is equal to the product of the tangents of the two adjacent parts. IL TJie **sine of the middle part is equal to the product of the cosines of the two opposite parts.** [B. p. 436.] Proof. To demonstrate the preceding rules, it is only necessary to compare all the equations... | |
| William Chauvenet - 1852 - 268 pages
...angle not being considered, the two sides including it are regarded as adjacent. The rules are : I. **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Benjamin Peirce - Trigonometry - 1852 - 382 pages
...parts ; and the other two parts are called the opposite parts. The two theorems are as follows. I. **The sine of the middle part is equal to the product of the** tangents of the two adjacent parts. II. The sine of the middle part is equal to the product of the... | |
| Elias Loomis - Trigonometry - 1855 - 192 pages
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and **the sine of the middle part, is equal to the product of the** tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
| George Roberts Perkins - Geometry - 1856 - 460 pages
...which are opposite, when either of the five parts is chosen as the middle part. NAPIER'S RULES, I. **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Henry William Jeans - 1858 - 106 pages
...selected is called the middle part. Eule A will apply to the former case, Eule B to the latter. RULE A. **The sine of the middle part is equal to the product of the** tangents of the two parts adjacent to it. EULE B. The sine of the middle part is equal to the product... | |
| Elias Loomis - Logarithms - 1859 - 372 pages
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and **the sine of the middle part, is equal to the product of the** tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
| John Daniel Runkle - Mathematics - 1859 - 478 pages
...RULES. BY TUI MAN HENRY 8AFFORD. IN the form in which they are usually given, the rules are — I. **The sine of the middle part is equal to the product of** tlie tangents of tJie adjacent parts. II. T/te sine of the middle part is equal to tJic product of... | |
| 1860 - 462 pages
...— RULE I. The sine of the middle pari equals the product of the cosines of the opposite parts. RULE **II. The sine of the middle part is equal to the product of the** tangents of the adjacent parts. That the second of these rules may be deduced from the first has been... | |
| George Roberts Perkins - Geometry - 1860 - 474 pages
...opposite, when either of the five parts is chosen as the middle part. 90°-B 90° -T NAPIER'S RULES. I. **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| |