 | Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...that it corresponds to one of the following invariable and comprehensive rules : 1. The radius into the sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal to the product... | |
 | Benjamin Peirce - Trigonometry - 1861 - 396 pages
...— I. The sine of the middle part is equal to the product of the tangents of the two adjacent parts. II. The sine of the middle part is equal to the product of the manes of the two opposite parts. [B., p. 438.] Proof. To demonstrate the preceding rules, .it is only... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...NAPIER. I. The sine of the middle part is equal to Hie product of tlte tangents of the adjacent parts. IL The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the results already... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...are called the opposite parts. Then, whatever be the middle part, we have as THE EULES OF NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of tJie cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with... | |
 | William Chauvenet - Trigonometry - 1863 - 272 pages
...»in» of the middle part и equal to the product of the tangents of the adjacent parte. II. The »ine of the middle part is equal to the product of the cosines of the opposite parts. The correctness of these rules will be shown by taking each of the five parts as middle... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...are called the opposite parts. Then, whatever be the middle part, we have as THE RULES ov NAPIKR. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. . II. The sine of the middle part is equal to the product of the cosines... | |
 | Benjamin Greenleaf - 1867 - 188 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the results already... | |
 | Eli Todd Tappan - Geometry - 1868 - 444 pages
...next to it are the adjacent parts, and the remaining two are the opposite parts. Napier's rule is : The sine of the middle part is equal to the product of the tangents of the adjacent parts, also to the product of the cosines of the opposite parts. The words... | |
 | Henry W. Jeans - 1873 - 272 pages
...substituted for cos. co. A ; cos. A for sin. co. A ; cot. A for tan. co. A, to. (See Part II.) KULE B. The sine of the middle part is equal to the product of the cosines of the two parts opposite to, or separated from it.* Having written down the equation according to the case, make... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
