 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...for practical purposes. 189. RULE. — Multiply each of the payments by the time in which it is due, and divide the sum of the products by the sum of the payments; the quotient will be the equated time of payment. •__ - ''• f 1 QUESTIONS FOR PRACTICE. 2. A owes B $380, to... | |
 | Daniel Adams - Arithmetic - 1833 - 268 pages
...find the mean time for several payments,' — RULE : — Multiply each sum by its time of payment, and divide the sum of the products by the sum of the payments, and the quotient will be the answer. Note. This rule is founded on the supposition, that what is gained... | |
 | A. Turnbull - Arithmetic - 1836 - 368 pages
...payer or re* ceiver, may be found, by multiplying each payment by the time ; then dividing the sum of the products, by the sum of the payments, the quotient is the equated or mean time at which the whole payments are due. This process is called EacATioN or PAYMENTS.... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...75-r-15=5 months, the answer. Hence the RULE. Multiply each payment by the time when it becomes due, and divide the sum of the products by the sum of the payments, and the quotient will be the time required. 2. A merchant has owing him $420, to be paid as follows... | |
 | Charles Davies - Arithmetic - 1838 - 292 pages
...the whole ? OPERATION. We here multiply each sum 200 x 2 = 400 by the time at which it becomes due, and divide the sum of the products by the sum of the payments. 200x4= 800 200x6 = 1200 600 )24|00 Ans. 4 months. . 3. A merchant owes $600, of which $100 is to be... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...will be the true equated time. RULE 2. Multiply each several payment by the time it has to run : then divide the sum of the products by the sum of the payments ; the quotient will be the equated time, nearly. Examples. IA owes B. S1800, whereof S200 is to. be paid at 6 months,... | |
 | Nathan Daboll - 1839 - 220 pages
...several debts, due at different times. RULE. Multiply each payment by the time at which it is due, then divide the sum of the products by the sum of the payments, and the quotient will be the answer. • . . EXAMPLES. 1. A owes B $380, to be paid $100 in 6 months,... | |
 | Daniel Adams - Arithmetic - 1840 - 278 pages
...find the mean lime for several payments, — RULE • — Multiply each sum by its time of payment, and divide the sum of the products by the sum of the payments, and the quotient will be the answer. Note. This rule is founded on the supposition, that what is gained... | |
 | Calvin Tracy - Arithmetic - 1840 - 316 pages
...following rule : RULE. — Multiply each payment by the time which must elapse before it becomes due, and divide the sum of the products by the sum of the payments. 2. A. owes me $50, payable in 4 months ; $100, payable in 10 months ; and $150, payable in 16 months.... | |
 | Daniel Adams - Arithmetic - 1848 - 316 pages
...6-j-days, Ans. Hence, To find the mean time of several payments, Multiply each sum by its time of payment, and divide the sum of the products by the sum of the payments. EXAMPLES FOR PRACTICE. 4. A western merchant owes in New York city $200, due in 5 months; $325'50,... | |
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Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit. 
