 ... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor...  The Elements of Algebra - Page 85by Elias Loomis - 1856 - 268 pagesFull view - About this book
 | Joseph Ray - Algebra - 1848 - 252 pages
...of the dividend by the first term of the divisor, the result will be the first term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor, the result will be the second... | |
 | Jeremiah Day, James Bates Thomson - Algebra - 1848 - 264 pages
...term, for the first term of the required root. III. Subtract the power from the given quantity, and divide the first term of the remainder by the first term of the root inrolved io the next inferior power and multiplied by the index of the given power ;* the quotient... | |
 | Charles Davies - Algebra - 1848 - 302 pages
...dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second... | |
 | George Roberts Perkins - Algebra - 1848 - 234 pages
...dividend by the first term, on the left of the divisor, the result is the fast term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. \ II. Then divide the fast term of the remainder by the fast term of the divisor, which gives the second... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...the remainder by the first term of the divisor, the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
 | Stephen Chase - Algebra - 1849 - 348 pages
...from the given polynomial. 3. Double the part of the root already found, for a partial divisor ; and divide the first term of the remainder by the first term of the doubled root; setting the quotient, with its proper sign, as a term both of the root and of the divisor.... | |
 | George Roberts Perkins - Algebra - 1850 - 276 pages
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient; multiply the divisor by this second term; and subtract... | |
 | William Smyth - Algebra - 1851 - 272 pages
...Multiply the divisor by this first term of the quotient and subtract the product from the dividend. 3°. Divide the first term of the remainder by the first term of the divisor, place the result in the quotient with its proper sign, multiply and subtract as before, and continue... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...the remainder by the first term oftlie divisor, the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...the remainder by the first term of the divisor; the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. 'Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
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