| George Campbell - Theology - 1840 - 450 pages
...instance, of the first kind, the following affirmations, " The cube of two is the half of sixteen." — " **The square of the hypothenuse is equal to the sum of the** squares of the sides." — " if equal' things be taken from equal things, the remainders will be equal."... | |
| John D. Williams - Algebra - 1840 - 634 pages
...area, yz is = to 2x, or у = — , and the hypothenuse of the triz 2a; angle is expressed by a z. But **the square of the hypothenuse is equal to the sum of the** squares of the two sides ; .•. (2x \2 4z8 4яа; а zl=— 5- — z", or о2 2<zz = — 4ах. Mulüz... | |
| Charles Davies - Navigation - 1841 - 414 pages
...round by either of the four last cases : or, if two of the sides are given, by means of the property **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
| Joseph Denison - Mechanics - 1841 - 210 pages
...circumference of the screw ; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) **the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular ; that is *' = A2 + c2 ; and extracting the square root of these... | |
| Adrien Marie Legendre - Geometry - 1841 - 288 pages
...others ; for the three figures will be proportional to the squares of their homologous sides ; now **the square of the hypothenuse is equal to the sum of the** squares of the two other sides ; therefore, &c. THEOREM. 223. The parts of two chords which cut each... | |
| Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...and the side B, C, 12 feet. What is the length of the side A, B? a In every right angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
| Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — **The square of the hypothenuse is equal to the sum of the** squares of the other two sides ; as, 503 = 40*+ 30s. [Fig. 8.] 16. Hence, to find the different sides,... | |
| Joseph Denison - Mechanics - 1841 - 210 pages
...circumference of the screw; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) **the square of the hypothenuse is equal to the sum of the** squares of the base and perpen-dicular ; that is * 2 — A 2 + c 2 ; and extracting the square root... | |
| Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — **The square of the hypothenuse is equal to the sum of the** squares of the other two sides ; as, 50" = 40" + 30!. [Fig. 8.] 16. Hence, to find the different sides,... | |
| Nathan Daboll - Arithmetic - 1843 - 254 pages
...perpendicular 48 rods, how many acres ? Ans. 7a. 2r. 36 rods. ART. 2. — In every right-angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides. 1. Hence, when the legs are given, to find the hypothenuse. RULE. Add... | |
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