 | Philotus Dean - Arithmetic - 1874 - 472 pages
...the true remainder is 500 + 47 = 547, and the complete quotient ig 71f§5Rule. Cut off the cipher or ciphers from the right of the divisor, and as many figures from the right of the dividend. Then divide the remaining figures of the dividend by the remaining figures of the divisor. If dividing... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 468 pages
...true remainder may be obtained by prefixing the second remainder to the first. Hence the RULE. I. Out off the ciphers from the right of the divisor, and...the right of the dividend. II. Divide the remaining figures of the dividend by the remaining figures of the divisor, for the final quotient. III. Prefix... | |
 | James Bates Thomson - 1875 - 392 pages
...answer. Hence, the RULE. — I. Cut off the ciphers on the right of the divisor and as many figures on the right of the dividend. II. Divide the remaining part of the dividend ly the remaining part of the divisor for the quotient. III. Annex the figures cut off to the remainder,... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...100. 782.85, or, 732flfo, Ana. CASE II. 43. When the divisor has one or more ciphers at the right. RULE. — I. Cut off the ciphers from the right of the divisor, and the same number of figures from the right of the dividend. II. Then divide the remaining figures of... | |
 | Edward Brooks - Arithmetic - 1877 - 564 pages
...200-|-56, or 256. 12-i!,,t Rule.—I. Gut off the ciphers at the right of the divisor, and as many terms at the right of the dividend. II. Divide the remaining...remaining part of the divisor. III. Prefix the remainder to the part of the dividend cut off, and the result will be the true remainder. NOTE.—When the divisor... | |
 | William James Milne - Arithmetic - 1877 - 418 pages
...Entire remainder 3321 t li miB a nds c timcs and 3 thonsand 6 thousands are contained in 39 RULE.—Gilt off the ciphers from the right of the divisor, and as many figures from the right of the dividend. Divide the rest of the dividend by the rest of the divisor. Annex to the remainder the figures cut... | |
 | Edward Brooks - Arithmetic - 1877 - 250 pages
...Gut off the ciphers at the right of the divisor and as many terms at the right of the dividend. 11. Divide the remaining part of the dividend by the remaining part of the divisor. III. Prefix the remainder to the part of the dividend cut off, and the result will be the true remainder. NOTES. — 1. When... | |
 | Edward Brooks - Arithmetic - 1877 - 438 pages
...Cut off the ciphers at the right of the divisor, md as many terms at the right of the dividend. 11. Divide the remaining part of the dividend by the remaining part of the divisor. III. Prefix the remainder to the part of the dividend cut tff, and the result will be the true remainder. NOTES. — 1. When... | |
 | Edward Brooks - Arithmetic - 1877 - 444 pages
...Cut off the ciphers at the right of the divisor, and as many terms at the right of the dividend. 11. Divide the remaining part of the dividend by the remaining part of the divisor. III. Prefix the remainder to the part of the dividend cut off, and the result will be the true remainder. NOTES. — 1. When... | |
 | Joseph Ray - Arithmetic - 1877 - 350 pages
...25|00)627|00(25г^Л SOLUTION. — The same as for the 50 example above. 127 125 Bule. — 1. Cut off the ciphers at the right of the divisor, and as many figures from the right of the dividend. 2. Divide the remaining figures in the dividend by the remaining figures in the divisor. 3. Annex the... | |
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I. Cut off the ciphers from the right of the divisor, and as many figures from the right of the dividend. II. Divide the remaining part of the dividend by the of the divisor. 
